Wich advantage of reproduction does the graph shown

You are designing an elevator for a hospital. The force exerted on a passenger by the floor of the elevator is not to exceed 1.7

HACTEHA [7]

Answer:

5.62 m/s

Explanation:

Newton's law of motion can be used to determine the maximum speed of the elevator. In the question, we are given:

Force exerted by the elevator (R) = 1.7 times the weight of the passenger (m*g)

Thus: R = 1.7*m*g

Distance (s) = 2.3 m

Newton's second law of motion: R - m*g = m*a

1.7*m*g - m*g = m*a

a = 0.7*m*g/m = 0.7*g = 0.7*9.8 = 6.86 m/s²

To determine the maximum speed:

$v^{2} _{f} = v^{2} _{i} + 2as$ $= 0 + 2(6.86)(2.3) = 31.556$

$v_{f} = \sqrt{31.556} = 5.62 m/s$

Therefore, the elevator maximum speed is equivalent to 5.62 m/s.

8 0

3 years ago

What is the minimum coeffecient of static friction μmin required between the ladder and the ground so that the ladder does not s

mars1129 [50]

Answer:

$\mu = \frac{1}{2tan\theta}$

Explanation:

let the ladder is of mass "m" and standing at an angle with the ground

So here by horizontal force balance we will have

$\mu N_1 = N_2$

by vertical force balance we have

$N_1 = mg$

now by torque balance about contact point on ground we will have

$mg(\frac{L}{2}cos\theta) = N_2(L sin\theta)$

so we will have

$N_2 = \frac{mg}{2tan\theta}$

now from first equation we have

$\mu (mg) = \frac{mg}{2tan\theta}$

$\mu = \frac{1}{2tan\theta}$

3 0

3 years ago

You have given a power supply, copper wire, and an iron nail. What should you do to decrease the strength of the electro magnet?

Viefleur [7K]

Explanation:

If you wrap some of the wire around the nail in one direction and some of the wire in the other direction, the magnetic fields from the different sections fight each other and cancel out, reducing the strength of your magnet

5 0

3 years ago

PLZ HELP ME!!!!!!!!

mote1985 [20]

Answer:

1. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.77955 m

now frequency is given by

$f = \frac{343m/s}{ 0.77955m}$

f = 440 Hz

2. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.52028 m

now frequency is given by

$f = \frac{343m/s}{ 0.52028m}$

f = 659.3 Hz

3. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.65552 m

now frequency is given by

$f = \frac{343m/s}{ 0.65552m}$

f = 523.25 Hz

4. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 587.33 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{587.33}$

$\lambda = 0.584 m$

5. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 493.88 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{493.88}$

$\lambda = 0.6945 m$

6. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 698.46 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{698.46}$

$\lambda = 0.491 m$

7. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.5840 m

now frequency is given by

$f = \frac{343m/s}{0.5840m}$

f = 587.3 Hz

8. Frequency = speed / wavelength

here we know

speed = 343 m/s

wavelength = 0.4375 m

now frequency is given by

$f = \frac{343m/s}{0.4375m}$

f = 784 Hz

9. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 783.99 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{783.99}$

$\lambda = 0.4375 m$

10. Wavelength = speed / Frequency

here we know

speed = 343 m/s

Frequency = 659.26 Hz

now wavelength is given by

$\lambda = \frac{343m/s}{659.26}$

$\lambda = 0.520 m$

4 0

3 years ago

Read 2 more answers

Determine the acceleration of a raptor that reaches 25 m/s from rest in 6.5 s.

REY [17]

Answer:

3.8 m/s²

Explanation:

Average acceleration is the change in velocity over change in time.

a = Δv / Δt

a = (25 m/s − 0 m/s) / 6.5 s

a ≈ 3.8 m/s²

8 0

3 years ago