What scientists use to make models of the Earth's water cycle so they can<span> see how it is ... Where </span>does<span> the water that we use to meet our everyday needs come from? .... what </span>you<span> notice about the </span>patterns<span> the</span>winds<span> and </span>clouds follow<span>: </span>Do clouds and<span> ... </span>same patterns<span>? </span>Can you find any patterns in the direction that they move? Precipitation is a vital component of how water moves through Earth’s water cycle, connecting
the ocean, land and atmosphere. Water evaporates from the surface of the land and oceans,
rises and cools, condenses into rain or snow, and falls again to the surface as precipitation. The
water falling on land collects in rivers and lakes, soil, and porous layers of rock, and much of it
flows back into the oceans. The cycling of water in and out of the atmosphere is a significant
aspect of the weather patterns on Earth. so that will be probs the best i can do
Answer:
a) 16m/s b) 192m
Explanation:
v1=32m/s a=-2m/s^2 t=8s v2=? d=??
a) I will use this equation v2= v1 + a*t
v2= 32m/s + -2m/s^2 * 8s
v2= 32m/s + -16m/s
v2= 16m/s
b) v2^2=v1^2 + 2ad
rearranging
v2^2-v1^2=2ad
v2^2-v1^2/2= a d
v2^2-v1^2/2a=d
16m/s^2 - 32m/s^2/ 2 x-2m/s^2 =d
d=192m
Answer:
Anticlockwise directions
Please mark me Brainliest to help me
Because the tip of the moon's shadow ... the area of "totality" ... is never more than a couple hundred miles across, It never covers a single place for more than 7 minutes, and can never stay on the Earth's surface for more than a few hours altogether during one eclipse.
If you're not inside that small area, you don't see a total eclipse.
Answer:
a) 3.39 × 10²³ atoms
b) 6.04 × 10⁻²¹ J
c) 1349.35 m/s
Explanation:
Given:
Diameter of the balloon, d = 29.6 cm = 0.296 m
Temperature, T = 19.0° C = 19 + 273 = 292 K
Pressure, P = 1.00 atm = 1.013 × 10⁵ Pa
Volume of the balloon = 
or
Volume of the balloon = 
or
Volume of the balloon, V = 0.0135 m³
Now,
From the relation,
PV = nRT
where,
n is the number of moles
R is the ideal gas constant = 8.314 kg⋅m²/s²⋅K⋅mol
on substituting the respective values, we get
1.013 × 10⁵ × 0.0135 = n × 8.314 × 292
or
n = 0.563
1 mol = 6.022 × 10²³ atoms
Thus,
0.563 moles will have = 0.563 × 6.022 × 10²³ atoms = 3.39 × 10²³ atoms
b) Average kinetic energy = 
where,
Boltzmann constant, 
Average kinetic energy = 
or
Average kinetic energy = 6.04 × 10⁻²¹ J
c) rms speed = 
where, m is the molar mass of the Helium = 0.004 Kg
or
rms speed = 
or
rms speed = 1349.35 m/s
