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2 years ago

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A 2.6 kg rock is dropped from a height of 10 m. With what speed will it strike the ground. Ignore air resistance. Solve using co

nservation of energy (start with Ebefore = Eafter).

1 answer:

timurjin [86]2 years ago

5 0

Answer:

$mgh = \frac{1}{2} m {v}^{2} \\ v = \sqrt{2gh} \\ = \sqrt{2 \times 9.8 \times 10} \: m. {s}^{ - 1}$

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