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3 years ago

15

A 2.6 kg rock is dropped from a height of 10 m. With what speed will it strike the ground. Ignore air resistance. Solve using co

nservation of energy (start with Ebefore = Eafter).

1 answer:

timurjin [86]3 years ago

5 0

Answer:

$mgh = \frac{1}{2} m {v}^{2} \\ v = \sqrt{2gh} \\ = \sqrt{2 \times 9.8 \times 10} \: m. {s}^{ - 1}$

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When a space shuttle was launched, the astronauts aboard experienced and acceleration of 29.0 m/s. If one of the astronauts had

ankoles [38]

   Net force = (mass) · (acceleration)

   = (69 kg) · (29 m/s²)

   = (69 · 29) · (kg·m/s²)

   = 2,001 Newtons upward
   (about 450 pounds)

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4 years ago

A 90.00-kg hockey goalie, at rest in front of the goal, stops a puck (m = 0.16 kg) that is traveling at 30.00 m/s. at what speed

Ivahew [28]

<span>5.3 cm/s This is a matter of conservation of momentum. Since there's no mention of the puck rebounding, I will consider this to be a totally non-elastic collision. So, let's determine the starting momentum of the system. Goalie is at rest, so his momentum is 0. Puck is moving at 30.00 m/s with a mass of 0.16 kg, so: 30.00 m/s * 0.16 kg = 4.8 kg*m/s So the starting momentum is 4.8 kg*m/s moving towards the goal. After the collision, the puck and goalie will have the same momentum. So figure out the mass of the new system: 90.00 kg + 0.16 kg = 90.16 kg And divide the system momentum by the system mass: 4.8 kg*m/s / 90.16 kg = 0.053238687 m/s Finally, round to the least precise datum, so the result to 2 significant figures is 0.053 m/s, or 5.3 cm/s.</span>

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4 years ago

True or false: Decreased output from the vasomotor center allows arterioles and veins to constrict.

wolverine [178]

<h3><u>Answer;</u></h3>

The above statement is False

<h3><u>Explanation;</u></h3>

Decreased output from the vasomotor center allows arterioles and veins to dilate.
The vasomotor center controls vessel tone or contraction of the smooth muscle in the tunica media.It is responsible for central regulation of cardiac electrical activity, myocardial performance, and peripheral vascular tone.
Changes in diameter affect peripheral resistance, pressure, and flow, which in turn affect cardiac output.

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3 years ago

Un cuerpo de 20 kg es lanzado verticalmente hacia arriba con una velocidad de 30 m/s. ¿Cuánto tiempo tardará el cuerpo en alcanz

nata0808 [166]

Answer:

tu hermana con salsa de concha

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3 years ago

A charged capacitor is connected to an ideal inductor to form an LC circuit with a frequency of oscillation f = 1.6 Hz. At time

IrinaK [193]

Answer:

$8.0\mu C$

Explanation:

We are given that

$f=1.6 Hz$

$q=3.0\mu C=3.0\times 10^{-6} C$

$1\mu C=10^{-6} C$

Current,I= $75\mu A=75\times 10^{-6} A$

$1\mu A=10^{-6} A$

We have to find the maximum charge of the capacitor.

Charge on the capacitor, $q=q_0cos\omega t$

$\omega=2\pi f=2\pi\times 1.6=3.2\pi rad/s$

$3\times 10^{-6}=q_0cos3.2\pi t$ ....(1)

$I=\frac{dq}{dt}=-q_0\omega sin\omega t$

$75\times 10^{-6}=-q_0(3.2\pi)sin3.2\pi t$ ....(2)

Equation (2) divided by equation (1)

$-3.2\pi tan3.2\pi t=\frac{75\times 10^{-6}}{3\times 10^{-6}}=25$

$tan3.2\pi t=-\frac{25}{3.2\pi}=-2.488$

$3.2\pi t=tan^{-1}(-2.488)=-1.188rad$

$q_0=\frac{q}{cos\omega t}=\frac{3\times 10^{-6}}{cos(-1.188)}=8.0\times 10^{-6}=8\mu C$

Hence, the maximum charge of the capacitor= $8.0\mu C$

4 0

4 years ago