Answer:
<h3>F=4k.gm/s^2</h3>
Explanation:
<h3>F=m×a</h3><h3>f=2k.g×2m/s^2</h3><h3>f=4k.gm/s^2</h3>
Answer:
The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m
Explanation:
The wavelength is defined for every periodic wave, that is, for the type of wave that repeats itself with exactly the same shape every given interval of time. It is the distance between two points from which the wave repeats.
Radiation is the emission, propagation and transfer of energy in any medium in the form of electromagnetic waves or particles.
The energy carried by electromagnetic radiation travels by waves. This energy is transmitted grouped in small "quanta" of energy called photons. The energy of a photon is measured in Joules (J) and is

Being:
- E=3.92×10⁻¹⁹ J
- h= 6.626×10⁻³⁴ J⋅s (Planck's constant)
- c = 2.99×10⁸ m/s (the speed of light)
- wavelength=?
and replacing:

you get:

wavelength= 5.054*10⁻⁷ m
<u><em>The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m</em></u>
It would decrease hope this helps
Answer:
i) Neon (Ne)
ii) Fluoride Ion (F⁻¹)
iii) Oxide Ion (O⁻²)
Explanation:
Ions are those charged species which are either positively charged (by loosing electrons) called as cations or negatively charged (by gaining electrons) called as anions.
In given examples, Neon is a neutral atom which has an atomic number 10. It contains 10 electrons in its neutral state with the electronic configuration 1s², 2s², 2p⁶.
Fluorine atom has an atomic number of 9. Therefore, it contains 9 electrons in its neutral state with an electronic configuration of 1s², 2s², 2p⁵. When Fluorine atom gains one electron it gets 10 electrons with electronic configuration of 1s², 2s², 2p⁶.
Oxygen atom has an atomic number of 8. Therefore, it contains 8 electrons in its neutral state with an electronic configuration of 1s², 2s², 2p⁴. When Oxygen atom gains two electron it gets 10 electrons with electronic configuration of 1s², 2s², 2p⁶ forming an Oxide Ion.