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3 years ago

What quantities vary between isotopes of an element

Chemistry

1 answer:

Montano1993 [528]3 years ago

8 0

Number of neutrons

nucleon number

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2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(g)

Ket [755]

Answer:- 10 L of ethane.

Solution:- The given balanced equation is:

$2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(g)$

From this equation, ethane and oxygen react in 2:7 mol ratio, the ratio of volumes would also be same if they are at same temperature and pressure.

Since 14 L of each gas are taken, the oxygen will be the limiting reactant and ethane will be the excess reactant. Let's calculate the volume of ethane used:

$14LO_2(\frac{2LC_2H_6}{7LO_2})$

= $4LC_2H_6$

From above calculations, 4 L of ethane are used. So, excess volume of ethane left after the completion of reaction = 14 L - 4 L = 10 L

Hence, 10 L of ethane will be remaining.

5 0

3 years ago

The specific heat of water is 4.18 j/(g⋅∘c). calculate the molar heat capacity of water. express your answer to three significan

iogann1982 [59]

Specific heat capacity of any substance comes with the unit : J/(g*degree C)
for molar capacity , change gram -> moles unit ( J / moles * degree C)

4.18 J / mol - degree C

H = 1.01 g * 2 = 2.02 g
O = 16 g

2.02 + 16 = 18.02 g

Now :- 4.18 J / mol- degree C) * 18.02 / 1 mole H2O
molar heat = 75.3 J / mol - degree C

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5 0

3 years ago

Read 2 more answers

the density of water at different temperature is listed in the table above. Based on this information we can predict that the de

son4ous [18]

look it nup on google should help

5 0

4 years ago

What is the percent of O in<br> CO2?

katen-ka-za [31]

Answer:

72.7% of oxygen

Explanation:

8 0

3 years ago

Please need this ASAP. Calculate the mass of lime, CaO, that would be produced from 250 tonnes of limestone,

stiv31 [10]

Answer:

1.4×10⁸ g of CaO

Explanation:

We'll begin by converting 250 tonnes to grams (g). This can be obtained as follow:

1 tonne = 1×10⁶ g

Therefore,

250 tonne = 250 × 1×10⁶

250 tonne = 2.5×10⁸ g

Next, the balanced equation for the reaction.

CaCO₃ —> CaO + CO₂

Next, we shall determine the mass of CaCO₃ that decomposed and the mass CaO produced from the balanced equation. This can be obtained as follow:

Molar mass of CaCO₃ = 40 + 12 + (16×3)

= 40 + 12 + 48

= 100 g/mol

Mass of CaCO₃ from the balanced equation = 1 × 100 = 100 g

Molar mass of CaO = 40 + 16

= 56 g/mol

Mass of CaO from the balanced equation = 1 × 56 = 56 g

SUMMARY:

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

Finally, we shall determine the mass of CaO produced by the decomposition of 250 tonnes (i.e 2.5×10⁸ g) of CaCO₃. This can be obtained as follow:

From the balanced equation above,

100 g of CaCO₃ decomposed to produce 56 g of CaO.

Therefore, 2.5×10⁸ g of CaCO₃ will decompose to produce =

(2.5×10⁸ × 56)/100 = 1.4×10⁸ g of CaO.

Thus, 1.4×10⁸ g of CaO will be obtained from 250 tonnes (i.e 2.5×10⁸ g) of CaCO₃.

6 0

3 years ago