Solution
x(t) = 8 cos t, x(5π/6)= 8 cos(<span>5π/6)
</span>cos(5π/6)=cos(3π/6 + 2π/6 )=cos(π/3 +π/2)= - sin π/3 (cos (x+<span>π/2)= -sinx)
</span>x(t) = -8sin <span>π/3 = - 4 .sqrt3
</span>v(t) = -8sint = -8sin (π/3 +<span>π/2)= -8 cosπ/3 </span>(sin (x+π/2)= cosx)
v(t) =<span> -8 cosπ/3 = -8/2= - 4
</span>a(5π/6) = - 8cost = -(- sin π/3)= 4 .<span>sqrt3
</span>a(5π/6) = 4 .<span>sqrt3</span>
same but who knows how 2021 might go
Hybrid
<u>Hybrid</u> modified the concept by adding an internal combustion engine and marketing hybrids that were part electric and part gas powered.
- The driving wheels of hybrid vehicles receive power from their drivetrains.
- A hybrid car has numerous sources of propulsion.
- There are numerous hybrid configurations.
- A hybrid vehicle might, for instance, get its energy from burning gasoline while alternating between an electric motor and a combustion engine.
- Although they have primarily been employed for rail locomotives, electrical vehicles have a long history of integrating internal combustion and electrical transmission, like in a diesel-electric power-train.
- Because the electric drive transmission directly substitutes the mechanical gearbox rather than serving as an additional source of motive power, a diesel-electric powertrain does not meet the definition of a hybrid.
- Only the electric/ICE hybrid car type was readily accessible on the market as of 2017.
- One type used parallel operation to power both motors at the same time.
- Another ran in series, using one source to supply power solely and the other to supply electricity.
- Either source may act as the main driving force, with the other source serving to strengthen the main.
To learn more about hybrid vehicles visit:
brainly.com/question/14610495
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Answer:
Yes
Explanation:
The spring force is given as:
F = kd
F is the spring force
K is the spring constant
d is the magnitude of the stretch
Since k is a constant, therefore, doubling the stretch distance will double the force.
Both stretch distance and force applied can be said to be directly proportional to one another.
We need to consider for this exercise the concept Drag Force and Torque. The equation of Drag force is
Where,
F_D = Drag Force
= Drag coefficient
A = Area
= Density
V = Velocity
Our values are given by,
(That is proper of a cone-shape)
Part A ) Replacing our values,
Part B ) To find the torque we apply the equation as follow,
