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Licemer1 [7]
3 years ago
9

Charina says that when waves interact with an object, they will interfere with the object, and when waves interact with other wa

ves, they will reflect off each other. do you agree with her? why or why not?
Physics
2 answers:
qaws [65]3 years ago
7 0

I completely don't agree with her, as a result of interference happens once waves act with alternative waves. Reflection happens once waves act with an associated object and bounce off it.

Explanation:

No, she has it backward. Waves interfere with one another and mirror off objects. once 2 waves overlap their amplitudes add. If they need a similar sign this addition is constructive, which means the amplitudes grow. If they need opposite signs this constitutes subtraction and also the waves will partly, or utterly cancel. this can be referred to as interference.

Reflection happens once waves travel from one medium to a different. If the wave electric resistance of the new medium is totally different (which it usually is) there'll be a partial, or maybe total, reflection.

Fofino [41]3 years ago
3 0
I would not agree with her since reflection and refraction happens only when waves hit an object. When, waves meet it is either it experiences constructive or destructive interference. Hope this answers the question. Have a nice day.
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Restate newton's first law in terms of acceleratin
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Well, I never heard it expressed that way before,
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777dan777 [17]

Newtons first law of motion.

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2 years ago
The force of gravity down on the boy= 300N
Leviafan [203]

The net force on the boy is zero.

Based on this analysis, I would expect the boy to <u>not accelerate</u>.


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(This is a non-relativistic warm-up problem, to get you to think about reference frames.) A girl throws a baseball upwards at ti
____ [38]

Answer:

X(t) = 9.8 *t - 4.9 * t^2

Explanation:

We set a frame of reference with origin at the hand of the girl the moment she releases the ball. We assume her hand will be in the same position when she catches it again. The positive X axis point upwards.The ball will be subject to a constant gravitational acceleration of -9.81 m/s^2.

We use the equation for position under constant acceleration:

X(t) = X0 + V0 * t + 1/2 * a *t^2

X0 = 0 because it is at the origin of the coordinate system.

We know that at t = 2, the position will be zero.

X(2) = 0 = V0 * 2 + 1/2 * -9.81 * 2^2

0 = 2 * V0 - 4.9 * 4

2 * V0 = 19.6

V0 = 9.8 m/s

Then the position of the ball as a function of time is:

X(t) = 9.8 *t - 4.9 * t^2

5 0
3 years ago
Just about everyone at one time or another has been burned by hot water or steam. This problem compares the heat input to your s
tatyana61 [14]

Answer:

Q_T=63313.5\ J

Explanation:

Given:

  • temperature of skin, T_s=34^{\circ}C
  • initial temperature of steam vapour, T_v=100^{\circ}C
  • latent heat of steam, L=2256\ J.g^{-1}
  • mass of steam, m=25\ g
  • specific heat of water, c=4190\ J.kg^{-1}.K^{-1}=4.19\ J.g^{-1}.K^{-1}
  • final temperature, T_f=34^{\circ}C

<em>Assuming that no heat is lost in the surrounding.</em>

<u>We know:</u>

Q=m.c.\Delta T

<u>Now the total heat given by the steam to form water at the given conditions:</u>

Q_T=Q_{Lv}+Q_w ..............................(1)

where:

Q_{Lv}= latent heat given out by vapour to form water of 100°C

Q_w= heat given by water of 100°C to come at 34°C.

putting respective values in eq. (1)

Q_T=m(L+c.\Delta T)

Q_T=25(2256+4.19\times 66)

Q_T=63313.5\ J

is the heat transferred to the skin.

4 0
3 years ago
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