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3 years ago

How did chemist Fritz Haber and engineer Carl Bosch contribute to society

Chemistry

1 answer:

Anettt [7]3 years ago

6 0

Chemist Fritz Haber and engineer Carl Bosch discovered a way to make ammonia efficiently.

They actually discovered a process that is Haber-Bosch process that is a process of nitrogen fixation that provides manufacturing of ammonia industially. Haber-Bosch process is an artificial process of nitrogen fixation. That is a process of manufacturing ammonia industially.

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If an atom of Carbon has 12 protons and 14 electrons what kind of ion is it and what is its charge?

Leto [7]

The answer will be Magnesium. It is a two positive ion and it can charge electrons and protons.

4 0

3 years ago

What is the mass in grams of 1 liter of nitrogen gas?

AlladinOne [14]

Assuming the volume of the gas is measured at standard temperature and pressure, Then one mole of the Gas would occupy 22.4 liters.

Therefore, 1 liter is 1/224 moles

one mole of nitrogen 14 is 14

Therefore 1 liter of the nitrogen weighs 1/224×14

0.0625 grams

7 0

3 years ago

15. What volume of CCI, (d = 1.6 g/cc) contain

anastassius [24]

Answer:

$\boxed{\text{(3) 9.6 L}}$

Explanation:

1. Moles of CCl₄

$n = 6.02 \times 10^{25} \text{ molecules} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ molecules}} = \text{100.0 mol}$

2. Molar mass of CCl₄

MM = 1 × 12.01 + 4 × 35.5 = 12.01 + 142 = 154.0 g/mol

3. Mass of CCl₄

$m =\text{100.0 mol} \times \dfrac{\text{154.0 g}}{\text{1 mol}} = \text{15 400 g}$

4. Volume of CCl₄

$V = \text{15 400 g} \times \dfrac{\text{1 cm}^{3}}{\text{1.6 g}} = \text{9600 cm}^{3}\\\\V = \text{9600 cm}^{3} \times \dfrac{\text{1 L}}{\text{1000 cm}^{3}} = \mathbf{{9.6 L}}\\\\\text{The volume of CCl$_{4}$ is } \boxed{\textbf{9.6 L}}$

4 0

3 years ago

In determining the energy of activation, why was it prudent to run the slowest trial done at room temperature in the hot water b

Katen [24]

Answer:In determining the energy of activation, why was it prudent to run the slowest trial done at room temperature in the hot water bath and the fastest trial done at room temperature in the cold water bath?

Explanation:

4 0

2 years ago

What mass of the protein gelatin is needed to make 0.5 L of a 3 g/L gelatin solution? Show your work.

REY [17]

Answer:

m = 1.5 gram

Explanation:

Given that,

Density of protein gelatin, d = 3 g/L

The volume of protein gelatin, V = 0.5 L

We need to find the mass of the protein gelatin. The density of an object is given by :

d = m/V

Where

m is mass

$m=d\times V\\\\m=3\ g/L\times 0.5\ L\\\\m=1.5\ g$

So, the required mass is 1.5 gram.

6 0

2 years ago