Answer:
The current would be same in both situation.
Explanation:
Given that,
Current I = 13 A
Number of turns = 23
We need to calculate the induced emf
Using formula of induced emf is
For N = 1
We need to calculate the current
Using formula of current
Put the value of emf
Now, if the number of turn is 22 , then induced emf would be
Then the current would be
Hence, The current would be same in both situation.
Answer:
281.25 J
Explanation:
We are told that the two objects with masses m and 3m.
Also that energy stored in the spring is 375 joules.
Now, initially the centre of mass of the system took place at rest, it means v1 = v and v2 = v/3
Thus, from principle of conservation of energy, we have;
½mv² + ½(3m)(v/3)² = 375J
(m + 3m/9)½v² = 375
(4/3)m × ½v² = 375
Multiply both sides by ¾ to get;
½mv² = 375 × ¾
½mv² = 281.25 J
Therefore, energy of lighter body is 281.25 J
Can someone help me with a question? At the local ski park, James earns 519.36 for working 32 hours. Create a double number line to identify the amount of money he would make for 1, 8 and 40 hours of work?
