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2 years ago

6

By using hydraulic cylinders of

1 answer:

JulsSmile [24]2 years ago

3 0

Answer:

C

Explanation:

Hydraulic systems can increase or decrease the force applied to them. To make the force larger, the pressure is applied to a larger area. For example, if a 100-N force is applied to the left cylinder in (Figure) and the right cylinder has an area five times greater, then the output force is 500 N.

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A private plane pilot is what kind of individual transportation position? professional level mid-level entry-level EPA-certified

gayaneshka [121]

Answer:

A private plane pilot is a mid-level position.

Explanation:

The six pilot certifications in the US are as follows:

Sport Pilot
Recreational Pilot
Private Plane Pilot
Commercial Plane Pilot
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Airline Transport Pilot

From this listing, it is evident that the Private Plane Pilot is in the mid of the line so it is a mid-level position.

3 0

2 years ago

A large spherical tank contains gas at a pressure of 400 psi. The tank is constructed of high-strength steel having a yield stre

jok3333 [9.3K]

Answer:

t=2.025 inches

Explanation:

Given that

P = 400 Psi

Yield stress ,σ = 80 ksi

Diameter ,d= 45 ft

We know that

1 ft = 12 inches

d= 540 inches

Factor of safety ,K= 3

The required thickness given as

$\dfrac {Pd}{4t}=\dfrac{\sigma}{K}$

t=thickness

$\dfrac {PdK}{4\sigma}=t$

$\dfrac {400\times 540\times 3}{4\times 80\times 1000}=t$

t=2.025 inches

Therefore thickness will be 2.025 inches.

5 0

3 years ago

Can somebody help me with that

skelet666 [1.2K]

Answer:

I think it's 23 ohms.

Explanation:

Not entirely sure about it.

hope this helps

4 0

2 years ago

A strain gauge with a 5 mm gauge length gives a displacement reading of 1.25 um. Calculate the stress value given by this displa

KengaRu [80]

Answer:

stress = 50MPa

Explanation:

given data:

Length of strain guage is 5mm

displacement $\delta = 1.25 \mu m =\frac{1.25}{1000} = 0.00125 mm$

stress due to displacement in structural steel can be determined by using following relation

$E =\frac{stress}{strain}$

$stress = E \times strain$

where E is young's modulus of elasticity

E for steel is 200 GPa

$stress = 200\times 10^3 *\frac{1.25*10^{-3}}{5}$

stress = 50MPa

7 0

3 years ago

Socket Programming: (30 points) Use Python TCP socket to implement an application with client-server architecture. In this appli

ololo11 [35]

Answer:

Explanation:

Run the code given in text file following instructions.

8 0

3 years ago