Answer:
A. 49.8L of NH3.
B. 33.83g.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is shown below:
N2 + 3H2 —> 2NH3
A. From the balanced equation above,
1L of N2 produced 2L of NH3.
Therefore, 24.9L of N2 will produce = 24.9 x 2 = 49.8L of NH3.
Therefore, 49.8L of NH3 is produced from the reaction.
B. Determination of the mass NH3 produced.
First, we shall determine the number of mole of NH3 produced. This can be obtained as follow:
Volume (V) = 49.8L
Pressure (P) = 97.8 kPa = 97.8/101.325 = 0.97atm
Temperature (T) = 23.7°C = 23.7°C + 273 = 296.7K
Gas constant (R) = 0.082atm.L/Kmol
Number of mole (n) =...?
PV = nRT
n = PV /RT
n = (0.97 x 49.8) / (0.082 x 296.3)
n = 1.99 mole
Next, we shall convert 1.99 mole to NH3 to grams. This is illustrated below:
Number of mole NH3 = 1.99 mole
Molar mass of NH3 = 14 + (3x1) = 17g/mol
Mass of NH3 =..?
Mass = mole x molar Mass
Mass of NH3 = 1.99 x 17
Mass of NH3 = 33.83g
Therefore, 33.83g of NH3 is produced.
