The ratio of output force to the input force is generally the mechanical advantage of the machine.
Answer:
The water shoots 15.31 m high above the street level.
Explanation:
The gauge pressure drives the motion of the water to whixhever height it will attain. The expression relating the gauge pressure to the height reached by the water, is
P = ρgh
P = Gauge Pressure = 150 kPa = 150,000 Pa
ρ = density of the fluid (water) = 1000 kg/m³
g = acceleration due to gravity = 9.8 m/s²
h = Height reached by the water = ?
150,000 = 1000 × 9.8 × h
h = (150000) ÷ 9800 = 15.306 = 15.31 m
Hope this Helps!!!
When using parallax, astronomers calculate distance from the sun and not earth to improve on the accuracy of their measurement, since parallax angle decreases as star distance increases.
<h3>
What is parallax distance?</h3>
Parallax enables astronomers to measure the distances of far away stars by using trigonometry.
<h3>Why does astronomers measure parallax distance from sun?</h3>
As the distance of star increases, the parallax angle decreases, and great degree of accuracy is required for its measurement.
So taking a refence from the earth instead of the sun will impact the accuracy of their measurement.
Thus, when using parallax, astronomers calculate distance from the sun and not earth to improve on the accuracy of their measurement, since parallax angle decreases as star distance increases.
Learn more about parallax distance here: brainly.com/question/2128443
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Answer:
(a) E=233.56 N/C
(b) The surface charge density of inner surface σ= -5.69×10⁻⁹C/m²
(c)The surface charge density of outer surface σ= 3.25×10⁻⁹C/m²
Explanation:
For Part (a)
The magnitude of the electric field at distance of 15.4 cm from the axis of the shell is given by:
E=λ/2πε₀r
Substitute the given values
Since the nonconducting rod positively charged,it induces a negative charge -q on the inner surface of conducting shell and a positive charge +q on the outer surface of conducting shell,so the net charge of conducting shell is zero
Part (b)
The surface charge density of inner surface is given by:
σ=-q/A
= -λ/2πr
Part(c)
Similarly the surface charge density on the outer surface of the cylindrical shell given by:
σ=λ/2πr