Answer:
a = -5.10 m/s^2
her acceleration on the rough ice is -5.10 m/s^2
Explanation:
The distance travelled on the rough ice is equal to the width of the rough ice.
distance d = 5.0 m
Initial speed u = 9.2 m/s
Final speed v = 5.8 m/s
The time taken to move through the rough ice can be calculated using the equation of motion;
d = 0.5(u+v)t
time t = 2d/(u+v)
Substituting the given values;
t = 2(5)/(9.2+5.8)
t = 2/3 = 0.66667 second
The acceleration is the change in velocity per unit time;
acceleration a = ∆v/t
a = (v-u)/t
Substituting the values;
a = (5.8-9.2)/0.66667
a = -5.099974500127
a = -5.10 m/s^2
her acceleration on the rough ice is -5.10 m/s^2
It’s c.) I think so at least
Answer:
6
Explanation:
because I did this assignment, :) your welcome
Next time do it by yourself, but here's the answer kid
The Answer is Option C
I think...
Sorry If i am wrong...
The correct answer is:

Let's see why.
1 amu corresponds to the mass of the proton, which is:

if we convert this into energy, using Einstein equivalence between mass and energy, we find:

Now we can convert it into electronvolts:

So, 1 amu = 934 MeV. Therefore, 3 amu corresponds to 3 times this value: