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Delicious77 [7]
2 years ago
10

A student uses a solution of potassium hydroxide to titrate a solution of nitric acid. Which question is the student trying to a

nswer?(1 point)
What is the concentration of nitric acid?
What is the concentration of nitric acid?

How much nitric acid solution is present?
How much nitric acid solution is present?

What is the concentration of potassium hydroxide?
What is the concentration of potassium hydroxide?

How many moles of potassium hydroxide are present?
How many moles of potassium hydroxide are present?
Chemistry
1 answer:
Mnenie [13.5K]2 years ago
4 0

Answer:

A. What is the concentration of nitric acid?

Explanation:

its right

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This will be named 2,4-dimethylpentane
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D. layer B is younger than layer G.
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I will give 25 points and make them brainlest if they solve this.
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B

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1. EXPLAIN the steps required to find the molar mass of NH3 . Also,
Natasha_Volkova [10]

Answer: Molar mass of NH_3 is 17.03 g

Explanation:

Molar mass is defined as the mass in grams of 1 mole of a substance.

S.I Unit of Molar mass is gram per mole and it is represented as g/mol.

It is found by adding the atomic masses of all the elements present.

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7 0
2 years ago
How many milliliters of 0.50 M KOH are needed
spayn [35]

Answer:

Option D. 30 mL.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above,

The mole ratio of the acid, nA = 1

The mole ratio of the base, nB = 1

Step 2:

Data obtained from the question. This include the following:

Volume of base, KOH (Vb) =.?

Molarity of base, KOH (Mb) = 0.5M

Volume of acid, HNO3 (Va) = 10mL

Molarity of acid, HNO3 (Ma) = 1.5M

Step 3:

Determination of the volume of the base, KOH needed for the reaction. This can be obtained as follow:

MaVa / MbVb = nA/nB

1.5 x 10 / 0.5 x Vb = 1

Cross multiply

0.5 x Vb = 1.5 x 10

Divide both side by 0.5

Vb = (1.5 x 10) /0.5

Vb = 30mL

Therefore, the volume of the base, KOH needed for the reaction is 30mL.

3 0
3 years ago
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