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mezya [45]
3 years ago
9

jane pushed a box with 15 N force (an action) what force does the box have on Jane? which law is this?

Physics
1 answer:
lord [1]3 years ago
5 0

Answer:

This is Newton’s third law (forces due to friction). There would be 15N being pushed back at Jane.

Explanation:

Newton’s third law states that for every action there is an equal and opposite reaction. So if Jane pushed with a force of 15N, 15N would be pushed back at her. Hope this helps! :)

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How is current related to voltage? ​
Tju [1.3M]

The relationship between current and voltage and resistance is described by ohlm's law. This equation i=v/r tells that the current i flowing through a circuit is directly proportional to the voltage v, and inversely proportional to resistance r. This desceibes the relationship of voltage, current and resistance.

8 0
4 years ago
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A vacuum cleaner produces sound with a measured sound level of 75.0 dB. (a) What is the intensity of this sound in W/m2? W/m2 (b
jonny [76]

Answer:

Part a)

I = 3.16 \times 10^{-5} W/m^2

Part b)

P_o = 0.162 Pa

Explanation:

Part a)

Level of sound = 75 dB

now we know that

L = 10 Log\frac{I}{I_0}

here we know that

I_0 = 10^{-12} W/m^2

now we have

75 = 10 Log(\frac{I}{10^{-12}})

I = 3.16 \times 10^{-5} W/m^2

Part b)

Intensity of sound wave is given as

I = \frac{1}{2}\rho A^2\omega^2 c

here we know that

A = \frac{P_o}{Bk}

so we have

I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c

I = \frac{1}{2}\rho P_o^2 \frac{c^3}{B^2}

now we know

\rho = 1.2 kg/m^3

c = 340 m/s

B = 1.4 \times 10^5 Pa

now we have

3.16 \times 10^{-5} = \frac{1}{2}(1.2)P_o^2\frac{340^3}{(1.4\times 10^5)^2}

P_o = 0.162 Pa

5 0
3 years ago
If a truck travels 100 miles in 2 hours, what is its speed?
miskamm [114]

Answer:50  miles per hour 50/1hr

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5 0
3 years ago
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A square-based shipping crate is being designed that must contain a volume of 16 ft3 . The material that is used for the base an
Vlada [557]

Answer:

Explanation:

Given

volume V=16 ft^3

Suppose base is square with side L

height of crate is h

Volume V=L^2\times h

16=L^2\times h

Cost of top and bottom area c_1=3L^2

Cost of Side area c_2=4Lh\times 2=8Lh=8L\times \frac{16}{L^2}=\frac{128}{L}

Total Cost C=c_1+c_2

Total Cost C=3L^2+\frac{128}{L}

Differentiate C w.r.t Length

\frac{dC}{dL}=6L-\frac{128}{L^2}

L^3=\frac{128}{6}

L=2.75 ft

h=\frac{16}{2.75^2}=11.46 ft

Dimensions are L\times L\times h=2.75\times 2.75\times 11.46    

6 0
3 years ago
What is the term for the principal that an object in motion remains in motion until it is met by an outside force?
Papessa [141]

The term for the principal that an object in motion remains in motion until it is met by an outside force is called inertia

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Every matter have inertia , a property to remain in that very position until unless it is been forced on them to change their position .

Inertia is a property of matter that causes it to resist changes in velocity (speed and/or direction). According to Newton's first law of motion, an object with a given velocity maintains that velocity unless acted on by an external force. Inertia is the property of matter that makes this law hold true.

To learn more about inertia here

brainly.com/question/1358512?referrer=searchResults

#SPJ4

7 0
2 years ago
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