All categories

3 years ago

Please help me out with this question if you help me I will give you the brain thing and extra points. 4/9 image below.

Chemistry

2 answers:

Alex_Xolod [135]3 years ago

8 0

Answer:

Explanation:

i think. hope you are doing well

gayaneshka [121]3 years ago

4 0

Answer:

It’s C

Explanation:

You might be interested in

Calculate the weight of 3.491 into 10 to the power 19 molecules of cl2

Rom4ik [11]

Answer:

The mass of 3.491 × 10¹⁹ molecules of Cl₂ of Cl₂ is 4.11 × 10⁻³ grams

Explanation:

The number of particles in one mole of a substance id=s given by the Avogadro's number which is approximately 6.023 × 10²³ particles

Therefore, we have;

One mole of Cl₂ gas, which is a compound, contains 6.023 × 10²³ individual molecules of Cl₂

3.491 × 10¹⁹ molecules of Cl₂ is equivalent to (3.491 × 10¹⁹)/(6.023 × 10²³) = 5.796 × 10⁻⁵ moles of Cl₂

The mass of one mole of Cl₂ = 70.906 g/mol

The mass of 5.796 × 10⁻⁵ moles of Cl₂ = 70.906 × 5.796 × 10^(-5) = 4.11 × 10⁻³ grams

Therefore;

The mass of 3.491 × 10¹⁹ molecules of Cl₂ of Cl₂ = 4.11 × 10⁻³ grams.

4 0

2 years ago

In an electroplating apparatus, where does the reduction reaction occur?

Ludmilka [50]

Answer:

on the surface of the cathode

6 0

1 year ago

During a reaction the following information was collected. Use this information to

Crazy boy [7]

D I have a good feeling about d

8 0

2 years ago

O2- is the Lewis ______ in the following reaction

matrenka [14]

$O^{2-}$ is the Lewis base in the following reaction:

$SO_3(g) + O^{2-}(aq)$ → $SO_4^{2-}(aq)$

<h3>What is lewis base? </h3>

Lewis base is a species that donates an electron pair.

In the above-given chemical equation, the $O^{2-}$ is the lewis base which is donating an electron pair to the central atom of $SO_3$ to form $SO_4^{-2}$ .

Hence, $O^{2-}$ is the Lewis base in the following reaction:

$SO_3(g) + O^{2-}(aq)$ → $SO_4^{2-}(aq)$

Learn more about the lewis base here:

brainly.com/question/15570523

#SPJ1

3 0

1 year ago

Does a precipitate form when a solution of calcium chloride and a solution of mercury(I) nitrate are mixed together? Write the n

olganol [36]

Answer : Yes, a precipitate form when a solution of calcium chloride and a solution of mercury(I) nitrate are mixed together.

The net ionic equation will be,

$2Hg^{+}(aq)+2Cl^{-}(aq)\rightarrow Hg_2Cl_2(s)$

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

$CaCl_2(aq)+2HgNO_3(aq)\rightarrow Ca(NO_3)_2(aq)+Hg_2Cl_2(s)$

The ionic equation in separated aqueous solution will be,

$Ca^{2+}(aq)+2Cl^{-}(aq)+2Hg^{+}(aq)+2NO_3^{-}(aq)\rightarrow Hg_2Cl_2(s)+Ca^{2+}(aq)+2NO_3^{-}(aq)$

In this equation, $Ca^{2+}\text{ and }NO_3^-$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$2Hg^{+}(aq)+2Cl^{-}(aq)\rightarrow Hg_2Cl_2(s)$

7 0

3 years ago