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3 years ago

A ball is thrown upward with an initial velocity of 22.0 m/s. If

Physics

1 answer:

Aleks04 [339]3 years ago

3 0

The maximum height reached by the ball during the upward motion is 24.7 m.

The given parameters;

initial velocity of the ball, u = 22 m/s

The maximum height reached by the ball is determined using the third kinematic equation as shown below;

v² = u² - 2gh

where;

v is the final velocity of the ball at the maximum height = 0
h is the maximum height attained by the ball

0 = u² - 2gh

2gh = u²

$h = \frac{u^2}{2g} \\\\h = \frac{22^2}{2(9.8)} \\\\h = 24.7 \ m$

Thus, the maximum height reached by the ball during the upward motion is 24.7 m.

Learn more here:brainly.com/question/24666225

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3 years ago

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3 years ago

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