If the impulse is 25 N-s, then so is the change in momentum.
The mass of the ball is extra, unneeded information.
Just to make sure, we can check out the units:
<u>Momentum</u> = (mass) x (speed) = <u>kg-meter / sec</u>
<u>Impulse</u> = (force) x (time) = (kg-meter / sec²) x (sec) = <u>kg-meter / sec</u>
Answer:
Time of flight = 4.08seconds
Horizontal component of initial velocity is 17.32m/s
Explanation: complete question( and the horizontal component of the initial velocity.)
The equation for time of flight of a projectile is given as T= 2u/g
T=( 2×20)/9.8
T= 40/9.8= 4.08seconds
Horizontal component of initial velocity Vix= Vi Costheta
Vix= 20× cos 30°
Vix= 20×0.8660
Vix= 17.32m/s
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Answer:
a. When the total displacement is -(A + B)
b. A + B = 1 m or -(A + B) = -11 m
c. 0 m
Explanation:
a. Under what circumstances can you end up back at your starting point?
If we have the displacement A and displacement B. The total displacement is A + B. We would end up at the starting point if we take a displacement -(A + B) from point B
b. What is the magnitude of the largest displacement you can end up from the starting point?
The maximum displacement we can obtain is when A and B are in the same direction. So A + B = 5 m + 6 m = 11 m or -A - B = -(A + B) = -11 m.
c. When A and B are perpendicular, what is the component of B in the direction of A?
Since A is perpendicular to B, the angle between A and B is 90°
So the component of B in A,s direction is Bcos90° = B × 0 = 0 m
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