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2 years ago

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An object accelerates from an initial Velocity of -3.87 m/s with a constant acceleration of 17.5 m/s ^ 2 How fast will it be tra

veling after it goes 187 m?

2 answers:

kondaur [170]2 years ago

6 0

I think that you typed that wrong

sergey [27]2 years ago

4 0

Answer:

what think u tyoed taht wrong

Explanation:

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Which of earths layers is made up of liquid metal

just olya [345]

The mantle. It is also the largest earth layer, making up about 84% of the earth.

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3 years ago

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Julia margaret cameron used a short focal length lens that allowed only a small area of sharp focus. what kind of effect would a

Klio2033 [76]

Julia margaret cameron used a short focal length lens that allowed only a small area of sharp focus. The effect that the lens like this produce would be Less Magnification and Wide Angle of view.

A lens having short focal length will produce Less Magnification and Wide Angle of view.

Short focal length gives a deeper depth of the present field in addition to the wide angle of view. They capture maximally that lies in their front of the camera to the infinity.

A lens with large focal length captures a narrow field band as compared to the one with short focal length.

The lower focal length shows the short depth of focus leading to less magnification.

Short focal length is determined by the radius of curvature of both the curvature of the lens, the medium of the surrounding and the refractive index of the lens given.

Focal length of camera shows how much band the camera is able to capture.

Learn more about Focal length here, brainly.com/question/16188698

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2 years ago

2) A 20 kg mass moving at a speed of 3 m/s is stopped by a constant force of 15 N. How many seconds must the force act on the ma

hammer [34]

Take the object's starting direction of motion to be the positive direction, so that a stopping force acts in the opposite direction. By Newton's second law, the object undergoes an acceleration <em>a</em> such that

-15 N = (20 kg) <em>a</em>

Solve for <em>a</em> :

<em>a</em> = - (15 N) / (20 kg) = -0.75 m/s²

The object's velocity <em>v</em> at time <em>t</em> is then given by

<em>v</em> = 3 m/s + (-0.75 m/s²) <em>t</em>

so the time it takes for the object to slow to a rest is

0 = 3 m/s + (-0.75 m/s²) <em>t</em>

<em>t</em> = (3 m/s) / (0.75 m/s²) = 4.0 s

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3 years ago

One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching this

Ne4ueva [31]

Answer:

In order to hit the same point with the second ball, you should throw it at an angle of 18° above the horizontal.

Explanation:

Horizontal reach formula for projectiles tells us

$d=\frac{v_i^2\sin(2\theta)}{g},$

where $v_i$ is the initial velocity and $\theta$ the angle above the horizontal.

Since for both shots the reach must be the same, we have

$\frac{v_i^2\sin(2\theta_1)}{g}=\frac{v_i^2\sin(2\theta_2)}{g}\\\sin(2\theta_1)=\sin(2\theta_2)\\\theta_2=\frac{1}{2}\arcsin(\sin(2\theta_1))=\frac{1}{2}\arcsin(\sin(2\times 72\deg))=\mathbf{18\deg}$ .

8 0

4 years ago

A 1000 kg train car traveling at 12 m/s on a level track has 400 kg of sand dumped, vertically, into it. What is the final speed

crimeas [40]

Answer:

The final speed of the train car is 8.57 m/s.

Explanation:

Given that,

Mass of train car = 1000 kg

Mass of sand = 400 kg

Speed of train car = 12 m/s

We need to calculate the final speed of the train car after the sand is dumped

Using conservation of momentum

$m_{1}u_{1}=(m_{1}+m_{2})v$ ...(I)

Put the value in the equation (I)

$1000\times12=(1000+400)v$

$v=\dfrac{1000\times12}{1400}$

$v=8.57\ m/s$

Hence, The final speed of the train car is 8.57 m/s.

5 0

3 years ago