Answer:
The answer would be A (distance traveled in a certain amount of time) !! I did the test ;w;
Answer:
Explanation:
Given
Total volume of tank
Suppose a is the side of cubical tank
volume of cubical tank
Answer:
K = 2 10⁻⁸ J
Explanation:
Let's solve this exercise in parts, we start by finding the charge on each plate of the capacitor
C = Q / ΔV
C = ε₀ A / d
ε₀ A / d = Q / ΔV
Q = ε₀ A ΔV / d (1)
indicate the potential difference ΔV₁ = 12 V, the distance between the plates d₁ = 3 mm = 0.003 m,
as the power supply is disconnected and the capacitor is ideal the charge remains constant
in the second part we separate the plates at d₂ = 5 mm = 0.005 m, using equation 1
ΔV₂ =
we substitute the equation for Q
ΔV₂ =
ΔV₂ =
in the third part we use the concepts of energy
starting point. Test charge near positive plate
Em₀ = U = q ΔV₂
final point. Test charge near negative plate
Em_f = K
energy is conserved
Em₀ = Em_f
q ΔV₂ = K
K = q ΔV₁
we calculate
K = 1 10⁻⁹ 12 0.005/0.003
K = 2 10⁻⁸ J
Answer:
(I). The store energy is 0.432 J.
(II). The energy density is 687.54 J/m³.
Explanation:
Given that,
Voltage = 12.0 V
Capacitor = 6.00 mf
Radius = 0.1 m
Distance = 10 mm
(I). We need to calculate the energy store
Using formula of store energy
Where, C = capacitor
V = voltage
Put the value into the formula
(II). We need to calculate the energy density
Using formula of energy density
Where, r = radius
d = distance
Put the value into the formula
Hence, (I). The store energy is 0.432 J.
(II). The energy density is 687.54 J/m³.
Answer:
An unbalanced force can change an object's motion. An unbalanced force acting on a still object could make the object start moving. An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving
Explanation:
hope this helps :)