Answer:
Which class r u in hmm ? Tell me okay
Required moles of CH₃COONa.3H₂O = Molarity x Volume of solution in L
= 0.100 M x (100.0 mL)
= 0.100 M x 0.100 L
= 0.01 mol
Required mass of CH₃COONa.3H₂O = Required moles x Molar mass
= 0.01 mol x (136.08 g / mol) = 1.3608 g
