In the presence of heat, copper (II) hydroxide decomposes in to copper (II) oxide.
Cu(OH)₂ (s) ----> CuO (s) + H₂O (l)
upon decomposition, water is removed from Cu(OH)₂
the amount of Cu(OH)₂ decomposed - 3.67 g
number of moles of Cu(OH)₂ - 3.67 g / 97.5 g/mol = 0.038 mol
stoichiometry of Cu(OH)₂ to CuO is 1:1
therefore number of CuO moles formed are - 0.038 mol
CuO reacts with sulfuric acid to form CuSO₄
CuO + H₂SO₄ ---> CuSO₄ + H₂O
stoichiometry of CuO to H₂SO₄ is 1:1
therefore number of H₂SO₄ moles that should react is 0.038 mol
the molarity of H₂SO₄ is 3M
this means that in 1000 ml - 3 mol of H₂SO₄ present
so if 3 mol are present in 1000 ml
then volume for 0.038 mol = 1000/3 * 0.038
= 12.67 ml
Answer:
ε = 201.5
Explanation:
Given data-
mass of benzene = 25.8 mg
= 25.8×10^-3 kg
Atomic mass of benzene= 78.11 amu
volume of hexane = 250.00 ml = 0.2500 L
Absorbance = 0.266
Length of the cell = 1.00 cm
Hence concentration =
solving we get
= 0.00132 M
Formula:
A= εcl
A= absorbance
c= concentration and l= length of cell
now substituting values in the above formula
0.266= ε×0.00132×1.000
⇒ε =
⇒ε = 201.5
Answer:
<h2>850.11 mL</h2>
Explanation:
The final volume can be found by using the formula for Boyle's law which is
Since we are finding the new volume
From the question we have
We have the final answer as
<h3>850.11 mL</h3>
Hope this helps you
Explanation:
As per Le Chatelier's principle, any disturbance caused in an equilibrium reaction will tend to shift the equilibrium in a direction away from the disturbance.
Since, the given reaction is exothermic in nature so, when we increase the temperature then reaction will shift in the direction opposing the increase in temperature. Hence, the equilibrium will shift on left side when we increase the temperature.
On the other hand, when we decrease the temperature then the equilibrium will shift on the right side.