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yulyashka [42]
3 years ago
6

Một vật đang chuyển động chịu tác dụng của hai lực cân bằng, thì

Physics
1 answer:
beks73 [17]3 years ago
8 0

Answer:

I can't open my account

Explanation:

q▪︎□□□●¤●●●●●●●●

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An object moves in uniform circular motion at 25 m/s and takes 1.0 second to go a quarter circle. What is the radius of the circ
FromTheMoon [43]
Object Motion: 25 m/s

Circumference of Circle: 
1/4 Circumference of Circle in 1 second = 25 meters
25 meters times 4 = Circumference of Circle 
Circumference = 100 meters

Formula to Find Circumference of Circle: (work opposite)
C = 2<span>πr

100 = </span>2πr          divided
100/2π = r         simplify
50/π = r         (exact radius)

Answer:
50/π meters = r         (exact radius)

4 0
3 years ago
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Leslie incorrectly balances an equation as 2C4H10 + 12O2 → 8CO2 + 10H2O.
tatiyna

Answer:

13 behind o2

Explanation:

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4 0
3 years ago
How does a rubber rod become negatively charged through friction?
stira [4]
I think it is c I'm only in 7th grade but I'm pretty sure that the answer is c
5 0
4 years ago
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You observe that a mass suspended by a spring takes 0.25 s to make a full oscillation. What is the frequency of this oscillation
Katarina [22]

Answer:

Frequency of oscillation, f = 4 Hz

time period, T = 0.25 s

Angular frequency, \omega = 25.13 rad/s

Given:

Time taken to make one oscillation, T = 0.25 s

Solution:

Frequency, f of oscillation is given as the reciprocal of time taken for one oscillation and is given by:

f = \frac{1}{T}

f = \frac{1}{0.25}

Frequency of oscillation, f = 4 Hz

The period of oscillation can be defined as the time taken by the suspended mass for completion of one oscillation.

Therefore, time period, T = 0.25 s

Angular frequency of oscillation is given by:

\omega = 2\pi \times f

\omega = 2\pi \times 4

\omega = 25.13 rad/s

5 0
3 years ago
Which pair of equations can describe the path of a particle moving with an acceleration that is perpendicular to the velocity of
antoniya [11.8K]

Answer:

The question clearly describes the circular motion.

The circular motion equation is

a_{radial} = \frac{v^2}{r}

The path of the particle is circular.

Explanation:

In circular motion, the radial acceleration is always towards the center and constant in magnitude. Furthermore, the velocity of the circular motion is always tangential to the circle, that is it is always perpendicular to the radius, hence the acceleration.

6 0
3 years ago
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