Answer: CO is a limiting reagent with regards to the Fe production.
Explanation:
Moles of CO = 
moles of 
According to reaction , 3 mole of CO reacts with 1 mole of 
then , 0.4714 moles of CO will react with : 
moles of that is 0.1571 moles.
0.4714 moles of CO will react with 0.1571 moles of which means that CO is present in limited amount acting as limiting reagent.
Mole remaining of = 0.2673 mol - 0.1571 mol = 0.1102 mol
Hence, CO is a limiting reagent and is an excessive reagent.
The molarity of a solution is defined as the moles of solute dissolved per kilogram of solvent. Therefore, we first compute the moles of KOH using:
Moles = mass / Mr
Moles = 23 / 56
Moles = 0.41
The volume of solvent is 1.6 liters
The density is 1 gram/cm³ = 1 kg/L
Mass of solvent = density * volume
Mass of solvent = 1 * 1.6
Mass of solvent = 1.6 kg
Molality = moles / kilogram
Molarity = 0.41 / 1.6
Molarity = 0.26
The molality of the solution is 0.26 molal.
Explanation:
When we move across a period from left to right then there will occur an increase in electronegativity and also there will occur an increase in non-metallic character of the elements.
As calcium (Ca) is a group 2A element and rubidium (Rb) is a group 1A element. Hence, Rb being an alkali metal is more metallic in nature than calcium (alkaline earth metal).
Both magnesium (Mg) and radium (Ra) are group 2A elements. And, when we move down a group then as the size of element increases so, it becomes easy of the metal atom to lose an electron.
As a result, there occurs an increase in metallic character of the element. Hence, Radium (Ra) is more metallic in nature than magnesium (Mg).
Also, both bromine and iodine are group 17 elements. Since, both of them are non-metals and non-metallic character increases on moving down the group.
Therefore, bromine (Br) is more metallic than iodine.
Answer:
The specific heat of water is 4.18 J/g C.
Explanation:
q
=
m
C
s
Δ
T
Never forget that!
2200
=
m
⋅
4.18
J
g
⋅
°
C
⋅
66
°
C
∴
m
≈
8.0
g
Let us calculate the structure of the electric shells of the Al atom. It has an atomic number of 13, so it has 13 electrons. The first 2 go to the first hell. The next 8 need to go to the second shell and the last 3 ones would go to the outermost shell. The outer shell, that is the most important one for chemical reactions, has thus 3 electrons. An atom always tries to have a completed outer shell (with either 2 or 8 atoms). It is easier for a cell to have a charge of +3 than a charge of -5 (smaller absolute value) and thus the Aluminum atom will try to get rid of the 3 electrons. In this process, it loses negative charge thus it will become positively charged. Hence, the correct answer is that it will prefer to lose 3 electrons and become positively charged.
