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jolli1 [7]
3 years ago
14

Which portion of the electromagnetic spectrum is used in a television

Physics
1 answer:
Alex_Xolod [135]3 years ago
8 0
<h2>Answer: Radio waves </h2>

Radio waves are a type of electromagnetic radiation with wavelengths between 10 m to 10,000 m. In the electromagnetic spectrum this wavelength is longer than infrared light and therefore, it goes beyond the visible spectrum.

This type of electromagnetic waves is very well reflected in the ionosphere, the layer of the atmosphere through which they travel directly or using repeaters.

In addition, they are very useful to transport information, being important in telecommunications. They are used not only for conventional radio transmissions but also in mobile telephony and <u>TV</u>.

It should be noted that since radio signals have large wavelengths, they can be diffracted around certain obstacles, such as hills and mountain ranges, preventing the signal from reaching its destination.

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Identify the type of chemical reaction that is described.
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the answer is rust 
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5 0
4 years ago
Think back to coulomb's law. two coins with identical charges are placed on a lab table 1.35 m apart.
ziro4ka [17]

The Coulomb’s law is expressed mathematically as:

F = k * q1 * q2 / d^2

Where,

F = force of attraction between 2 particles = 2.0 N

<span> k = Coulomb’s constant = 8.988 * 10^9 N m^2 / C^2</span>

q = charge of the particle

d = distance between the 2 particles = 1.35 m

 

Since the two coins have identical charges therefore q1 = q2 =q

F = k* q^2 / d^2

2.0 N = (8.988 * 10^9 N m^2 / C^2) * q^2 / (1.35 m)^2

q = 2.01 * 10^-5 C

<span>Therefore each coins have charges equivalent to 2.01 * 10^-5 C.</span>

4 0
4 years ago
Can two like charges attract each other
seropon [69]

Answer:

Can two like charges attract each other : True ( Yes)

3 0
3 years ago
Which of these is an example of energy transfer by radiation?
andrezito [222]

Answer:

Hands rubbed together to become warm

6 0
3 years ago
Read 2 more answers
A 1470-kilogram truck moving with a speed of 27.0 m/s runs into the rear end of a 1010-kilogram stationary car. If the collision
Gre4nikov [31]

Answer:

\Delta KE = 218.375\ kJ

Explanation:

Given,

Mass of the truck, M =  1470 Kg

initial speed of the truck, u = 27 m/s

mass of car, m = 1010 Kg

initial speed of car, u' = 0 m/s

Final speed, V = ?

Using conservation of momentum

Mu = (M+m) V

1470\times 27 = (1470 + 1010 ) V

V = 16\ m/s

Change in kinetic energy

\Delta KE = \dfrac{1}{2} Mu^2 - \dfrac{1}{2}(M+m)V^2

\Delta KE = \dfrac{1}{2}\times 1470\times 27^2 - \dfrac{1}{2}\times (1470 + 1010)\times 16^2

\Delta KE = 218.375\ kJ

Change in KE = \Delta KE = 218.375\ kJ

3 0
3 years ago
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