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Svet_ta [14]
3 years ago
13

What limitations exist when attempting to categorize hair by race?

Physics
1 answer:
almond37 [142]3 years ago
6 0

Answer:

Albino possibilities

Explanation:

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Based on its surface features, the most important event on Venus in the past billion years or so was _______.a) the eruption of
ira [324]

Answer:

Correct answer is (c) a global "repaving" that erased essentially all the surface features that had existed earlier

Explanation:

Venus underwent cyclic process which erased the proved of other craters about billion years back. This is termed Venus global resurfacing event.

4 0
3 years ago
An object accelerates from rest with a constant acceleration of 7.5 m/s2. How fast will it
Serhud [2]

Answer:

13.4 m/s

Explanation:

Given:

Δx = 12 m

v₀ = 0 m/s

a = 7.5 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (7.5 m/s²) (12 m)

v ≈ 13.4 m/s

8 0
3 years ago
A particularly beautiful note reaching your ear from a rare stradivarius violin has a wavelength of 39.1 cm. the room is slightl
raketka [301]
The wavelength of the note is \lambda = 39.1 cm = 0.391 m. Since the speed of the wave is the speed of sound, c=344 m/s, the frequency of the note is
f= \frac{c}{\lambda}=879.8 Hz

Then, we know that the frequency of a vibrating string is related to the tension T of the string and its length L by
f= \frac{1}{2L} \sqrt{ \frac{T}{\mu} }
where \mu=0.550 g/m = 0.550 \cdot 10^{-3} kg/m is the linear mass density of our string.
Using the value of the tension, T=160 N, and the frequency we just found, we can calculate the length of the string, L:
L= \frac{1}{2f}  \sqrt{ \frac{T}{\mu} } =0.31 m
8 0
3 years ago
The force of gravity considers which two parts?
attashe74 [19]
Mass of object/source
Gravity
Fg=mg
3 0
2 years ago
A hollow cylinder of mass 2.00 kg, inner radius 0.100 m, and outer radius 0.200 m is free to rotate without friction around a ho
Aneli [31]

Answer:

h=2.86m

Explanation:

In order to give a quick response to this exercise we will use the equations of conservation of kinetic and potential energy, the equation is given by,

\Delta PE_i + \Delta KE_i = \Delta PE_f +\Delta KE_f

There is no kinetic energy in the initial state, nor potential energy in the end,

mgh+0=0+KE_f

In the final kinetic energy, the energy contributed by the Inertia must be considered, as well,

mgh = (\frac{1}{2}mv^2+\frac{1}{2}I\omega^2)

The inertia of the bodies is given by the equation,

I=\frac{m(R_1^2+R^2_2)}{2}

I=\frac{2(0.2^2+0.1^2)}{2}

I=0.05Kgm^2

On the other hand the angular velocity is given by

\omega =\frac{v}{R_2}=\frac{4}{1/5} = 2rad/s

Replacing these values in the equation,

(0.5)(9.8)(h) =\frac{1}{2}*0.5*4^2+\frac{1}{2}*0.05*20^2

Solving for h,

h=2.86m

5 0
2 years ago
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