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azamat
4 years ago
14

A certain element x has four isotopes. 94.93% of x has a mass of 31.97207 amu . 0.7640% of x has a mass of 32.97146 amu . 4.290%

of x has a mass of 33.96786 amu . 1.600×10−2% of x has a mass of 35.96709 amu . what is the average atomic mass of element x ?
Chemistry
1 answer:
Ede4ka [16]4 years ago
5 0
Average atomic mass is the weighted average atomic mass of an element with regard to the abundance of all its isotopes.
average atomic mass of X can be calculates as follows;
average atomic mass of X = sum of the products of mass of isotopes by their abundance percentages
average atomic mass of X = (94.93 % x 31.97207 amu) + (0.7640% x 32.97146 amu) + (4.290% x 33.96786 amu) + (1.600×10−2% x <span>35.96709 amu) 

</span>average atomic mass of X = 30.35 + 0.2519 + 1.457 + 0.005755
therefore average atomic mass of X = 32.06 
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6 mols H2 are needed

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Which of the following statements is a qualitative observation? A.The branch is three meters long. B.The substance tastes bitter
notka56 [123]

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3 years ago
What is the volume, in milliliters, occupied by 30.07 g of an object of density equal to
den301095 [7]

Answer:

\boxed {\tt 20.317567567568 \ mL}

Explanation:

The density formula is:

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Let's rearrange the formula for v. the volume. Multiply both sides by v, then divide by d.

d*v=\frac{m}{v}*v

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The volume can be found by dividing the mass by the density. The mass of the object is 30.07 grams and the density is 1.48 grams per milliliter.

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Divide. Note, when dividing, the grams, or g will cancel out.

v= \frac{30.07}{1.48 \ mL}

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The volume of the object is 20.317567567568 milliliters.

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4 years ago
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