The atomic mass is determined by the number of protons and neutrons in a atoms for example oxygen has eight protons and neutrons which gives oxygen and atomic mass of 16
It's just H20 but with 3 water molecules
This is a tricky question. a mole of any compound contains the same number of molecules of that certain compound. so, one mole of chlorine gas has the same number of molecules as one mole of glucose, which is 6.02 x 10^23.
this is avogadro's number and it applies for any mole of molecules.
the question is tricky because it is like asking. " what weighs more, a pound of feathers or a pound of rocks?" the both weigh the same, a pound. when ewe talking about moles, same as pounds, it is a quantity unit. one mole will aways be equal to 6.02 x 10^23 molecules.
We are going to use this formula:
E° = 0.0592/ n * ㏒K
when E° is the standard state cell potential
and n is number of moles of electrons transferred in the balanced equation
for the reaction of the cell.
Sr(s) + Mg2+ (aq) ↔ Sr2+(aq) + Mg(s)
we can get it by using the given balanced equation, we here have 2 electrons
transferred so, n = 2
and K the equilibrium constant = 3.69 x 10^17
so, by substitution:
∴ E° = 0.0592 / 2 * ㏒ (3.69 x 10^17)
= 0.52 V
Answer:
The rate at which sulfur dioxide is being produced is 0.90 kg/s.
Explanation:
Volume of oxygen gas consumed in second ,V= 994 L
Pressure of the gas = p
Temperature of the gas = T = 170°C= 170 + 273 K=443 K
Moles of oxygen gas consumed in a second = n
( ideapl gas equation)

n = 21.044 mole
Moles of dioxygen gas consumed per second = 21.044 mol
(Claus process)
According to reaction, 3 moles of dioxygen gives 2 moles of sulfur dioxide gas.Then 21.044 moles of dioxygen will give;
of sulfur dioxide
Mass of 14.029 moles of sulfur dioxide gas;
14.029 mol × 64 g/mol = 897.86 g
897.86 g = 0.89786 kg ≈ 0.90 kg
Mass of sulfur dioxide produced per second = 0.90 kg
The rate at which sulfur dioxide is being produced is 0.90 kg/s.