Explanation:
The given data is as follows.
Volume = 1 L, Concentration of Ca = 5 ppm or 5 mg/L
As 1 mg = 0.001 g so, 5 mg /L will be equal to 0.005 g/l. Molar mass of calcium is 40.078 g/mol.
Hence, calculate molarity of calcium as follows.
Molarity of Ca = 
= 
Molarity of Ca = 
Hence, molarity of 
is . Since, volume is same so, moles of calcium chloride will be 
.
Thus, we can conclude that mass of will be as follows.
(molar mass of = 110.984 g/mol)
= 0.0138 g
Thus, we can conclude that mass of is 0.0138 g.
Answer:
296.448 g
Explanation:
Density:
we know that density of an object can be measured by dividing its mass to its volume.
Symbol:
The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m= mass
V= volume
Given data:
volume= 1.2 cm x 4.00 cm x 3.20 cm =15.36 cm3
density= 19.3 g/cm3
mass=?
Now we will put the values in the formula,
d=m/v
d x V= m
m = 15.36 cm3 x 19.3 g/cm3
m=296.448 g
so the mass of block of gold is 296.448 g
Answer:
For this angular momentum, no quantum number exist
Explanation:
From the question we are told that
The magnitude of the angular momentum is 
The generally formula for Orbital angular momentum is mathematically represented as
Where 
is the quantum number
now
We can look at the given angular momentum in this form as
comparing this equation to the generally equation for Orbital angular momentum
We see that there is no quantum number that would satisfy this equation
Nobody knows this answer I checked a bunch of websites and they all don't know the answer.
