This is how far I got:
put equation 3. into 1. together with h = 5:
4.
when I double m₁ the ratio becomes:
5.
when I put these to ratios back into equation nr 1 and nr2, I find the ratio:
and new v₁ = 2.95
I'm not sure this is correct.
Answer:
The work done by Joe, W_joe, when he raises the barbell to finish one repetition is 211.98J
The correct option is Wsam <W_Joe.
Explanation:
From the mass of the bar, the acceleration of gravity and the distance that the bar travels in each of them when performing the lifting movement from the chest you can calculate the work done by each one:
W_joe= 31.5kg × 9.81 (m/s^{2} ) × 0.686m = 211.98J
W_sam= 31.5kg × 9.81 (m/s^{2} ) × 0.608m = 187.88J
187.88J < 211.98J ⇒ Wsam <W_Joe
im probably wrong but probably increase because if they get closer the static/sparks to cause a reaction
Answer:
True
Explanation:
Assuming no wind resistance, there will be no horizontal acceleration, because there will be no forces acting on it.
Answer: 0.145 seconds
Explanation:
Given that Roger Clemens could routinely throw a fastball at a horizontal speed of 119.7 m/s. How long did the ball take to reach home plate 17.3 m away
Since the speed is horizontal
Using the formula for speed which is
Speed = distance/time
Where
Speed = 119.7 m/s
Distance covered = 17.3 m
Time is what we are looking for
Substitute all the parameters into the formula
119.7 = 17.3/ time
Make time the subject of formula
Time = 17.3 / 119.7
Time = 0.145 seconds.
Therefore, it will take 0.145 seconds to reach the home plates