Question

Calculate the density, in g/l, of sf6 gas at 27°c and 0.500 atm pressure.

Answer 1

The density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.

The given parameters:

• temperature of the SF₆ gas, T = 27 ⁰C = 273 + 27 = 300 K
• pressure of the SF₆ gas, P = 0.5 atm

The molecular mass of the SF₆ gas is calculated as follows;

M of SF₆ = 32 + (6 x 19) = 146 g/mol

The density of the SF₆ gas is calculated by applying ideal gas law as follows;

$PV = nRT\\\\PV = \frac{m}{M} RT\\\\PM = \frac{m}{V} RT\\\\PM = \rho RT\\\\\rho = \frac{PM}{RT}$

where;

• $\rho$ is the density of the gas
• R is the ideal gas constant = 0.0821 L.atm/mol.K

$\rho = \frac{0.5 \times 146}{0.0821 \times 300} \\\\\rho = 2.96 \ g/l$

Thus, the density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.

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