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anygoal [31]
2 years ago
14

Divers in Acapulco dive from a cliff that is 65 m high. If the rocks

Physics
1 answer:
Alex777 [14]2 years ago
5 0

Answer:

Cool question! First step is to find the time taken to fall

57

m

, then to find the horizontal velocity needed to cover

24

m

in that time. In this case the answer is

7.0

m

s

−

1

.

Explanation:

This is a less typical projectile motion question, but it's still projectile motion. This means the horizontal and vertical directions can be considered separately. We assume that the initial vertical velocity,

u

y

=

0

m

s

−

1

, and we are trying to find the required initial horizontal velocity,

u

x

.

To find the time taken to fall

57

m

:

s

=

u

t

+

1

2

a

t

2

Since

u

=

0

, we can rearrange this to:

t

=

√

2

s

a

=

√

2

⋅

57

9.8

=

3.41

s

The horizontal velocity will be constant (ignoring air resistance), so to cover

24

m

in

3.41

s

will be given by:

v

=

s

t

→

u

x

=

24

3.41

=

7.0

m

s

−

1

Answer link

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A parallel plate capacitor creates a uniform electric field of and its plates are separated by . A proton is placed at rest next
zalisa [80]

Complete Question

A parallel plate capacitor creates a uniform electric field of 5 x 10^4 N/C and its plates are separated by 2 x 10^{-3}'m. A proton is placed at rest next to the positive plate and then released and moves toward the negative plate. When the proton arrives at the negative plate, what is its speed?

Answer:

V=1.4*10^5m/s

Explanation:

From the question we are told that:

Electric field B=1.5*10N/C

Distance d=2 x 10^{-3}

At negative plate

Generally the equation for Velocity is mathematically given by

V^2=2as

Therefore

V^2=\frac{2*e_0E*d}{m}

V^2=\frac{2*1.6*10^{-19}(5*10^4)*2 * 10^{-3}}{1.67*10^{-28}}

V=\sqrt{19.2*10^9}

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5 0
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What happens when charged object is brought near uncharged object?<br> Attract or Repel ?
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Larry drops a 5kg ball off of a building. The ball hits the ground 4.7s later. How tall is the building?
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Explanation:

Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 4.7 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (4.7 s) + ½ (9.8 m/s²) (4.7 s)²

Δy ≈ 110 m

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3 years ago
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