CrO as we need to find the empirical formula (simplest formula) not molecular formula
The molarity of acetic acid in the vinegar is 0.94 M
<u><em> calculation</em></u>
Step 1: write the balanced equation between CH3COOH + NaOH
that is CH3COOH + NaOH → CH3COONa + H2O
step 2 : find the moles of NaOH
moles =molarity x volume in L
volume in liters = 26.90/1000=0.0269 l
moles = 0.175 mol /L x 0.0269 L =0.0047 moles of NaOH
Step 3: use the mole ratio to find moles of CH3COOH
that is the mole ratio of CH3COOH: NaOH is 1:1 therefore the moles of CH3COOH is =0.0047 moles
Step 4: find the molarity of CH3COOH
molarity = moles/volume in liters
volume in liter = 5.00/1000 =0.005 l
molarity is therefore=0.0047 moles/ 0.005 l = 0.94 M
Answer:
Gases act more ideal at lower pressure <u>beacuse</u><u> </u><u>t</u><u>he</u><u> </u><u>attractive</u><u> </u><u>forces</u><u> </u><u>between</u><u> </u><u>molecules</u><u> </u><u>will</u><u> </u><u>decrease</u><u> </u><u>or</u><u> </u><u>become</u><u> </u><u>less</u><u> </u><u>significant</u><u> </u><u>compared</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>empty</u><u> </u><u>space</u><u> </u><u>between</u><u> </u><u>them</u><u>.</u>
Explanation:
Generally, a gas behaves more like an ideal gas at higher temperature and lower pressure as the potential energy due to intermolecular forces becomes less significant compared with the particles "kinetic energy" and the size of the molecules become less significant compared to the empty space between them.
Attractive forces between molecules, decrease the pressure of a reak gas, slowing the molecules and reducing collisions with the walls.The higher the value of a gas, the greater the attraction between molecules and the more easily the gas will compress.
<h2>HOPE IT HELPS MUCH</h2>
answered by: <em><u>J</u></em><em><u>o</u></em><em><u>h</u></em><em><u>n</u></em><em><u> </u></em><em><u>Glenly</u></em><em><u> </u></em><em><u>Pillazo</u></em><em><u> </u></em><em><u>M</u></em><em><u>a</u></em><em><u>h</u></em><em><u>u</u></em><em><u>s</u></em><em><u>a</u></em><em><u>y</u></em>