Answer:
1: CO2 cycle
2: soil respiration
3: in soil repiration grass regenerates and is ready for gazing, the carbon will be sequestered again when the animals return. then CO2 is released into the atmosphere.
Answer:
Mass is the measure of how much matter is in an object
Explanation:
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Answer:
Explanation:
This is a skeleton problem because the reacting species are not given. We do not have any information about the metal and non-metal reacting. Let us give a run down on how to solve this kind of problem. I hope you find it useful.
Firstly, establish the reaction equation. This will contain the reactants and products. The equation must be balanced in order to comply with the law of conservation of matter.
Secondly, solve from the known to the unknown specie. The known is the one which we can accurately determine the number of moles from. Using the number of moles of the known, we can find the moles of the unknown.
To find the number of moles;
Number of moles = 
molar mass is the sum of the atomic masses of the given compound whose mass we know.
mass = 5g
Thirdly; compared the number of moles of the known to the unknown using relationships and ratios between the two of them. F
For example, if :
2 mole of known gives 1 moles of unknown
solved mole of the known will give
moles of unknown
Lastly:
Now use this mole to find the mass of the unknown;
Mass of unknown = number of moles of unknown x molar mass
Answer:
<h3>The answer is 0.75 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula

From the question we have

We have the final answer as
<h3>0.75 g/mL</h3>
Hope this helps you
The Ksp of PbSO₄ = 2.53 × 10⁻⁷
for srSO₄→ 3.44 × 10⁻⁷
for srSO₄
srSO₄→ Sr²⁺ + SO₄⁻
Ksp = [sr²⁺] [SO₄⁻]
3.44 ˣ 10⁻⁷ = (0.0330M) [ SO₄⁻]
[SO₄⁻] = 8.1 ˣ 10⁻⁶M
foe Pb SO₄
PbSO₄ →Pb²⁺ + SO₄⁻
Ksp = [ Pb²⁺] [ SO₄⁻]
2.53 ˣ 10⁻⁸M
= [ Pb²⁺] (8.1 ˣ10⁻⁶M)
[Pb²⁺] = 2.75 ˣ 10⁻³M