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prohojiy [21]
3 years ago
13

.a car increases its speed from 10 m/s to 20/s in 2.5. seconds calculate it’s acceleration

Physics
1 answer:
Mekhanik [1.2K]3 years ago
3 0

Answer:

\boxed {\boxed {\sf 4\ m/s^2}}

Explanation:

Acceleration is the rate of change of an object with respect to time. It is the change in velocity over the time.

a= \frac{v_f-v_i}{t}

The car starts at 10 meters per second and increases to 20 meters per second in 2.5 seconds.

  • v_f= 20 m/s
  • v_i= 10 m/s
  • t= 2.5 s

Substitute the values into the formula.

a= \frac{ 20 \ m/s - 10 \ m/s}{2.5 \ s }

Solve the numerator.

a= \frac{10 \ m/s}{2.5 \ s}

Divide.

a= 4 \ m/s/s

a= 4\ m/s^2

The acceleration of the car is <u>4 meters per second squared.</u>

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Answer:

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Explanation:

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3 years ago
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In a heat engine, Qh and Qc represents high temperature substance and low temperature substance respectively. Which of the follo
ElenaW [278]

The efficiency of a heat engine is given by the expression eff =\frac{Q_h-Q_c}{Q_h}

The efficiency of a heat engine is the ratio of the work done by the engine to the heat given as the input to the engine.

eff =\frac{W}{Q_h}

The heat engine absorbs Q h from the hot reservoir , performs a work <em>W</em> on the absorbed heat and rejects Qc to the cold reservoir.

Therefore, the work done  is given by,

W=Q_h - Q_c

Thus the efficiency is given by, eff =\frac{Q_h-Q_c}{Q_h}

6 0
3 years ago
Chegg ) Alice owns 20 grams of a radioactive isotope that has a half-life of ln(4) years. (a) Find an equation for the mass m(t)
stepladder [879]

Answer:

m(t)=20e^{-0.5t}

Explanation:

Given:

Initial mass of isotope (m₀) = 20 g

Half life of the isotope (t_{1/2}) = (ln 4) years

The general form for the radioactive decay of a radioactive isotope is given as:

m(t)=m_0e^{-kt}

Where,

m(t)\to mass\ after\ 't'\ years\\t\to years\ passed\\k\to rate\ of\ decay\ per\ year

So, the equation is: m(t)=20e^{-kt}

At half-life, the mass is reduced to half of the initial value.

So, at t=t_{1/2},m(t)=\frac{m_0}{2}. Plug in these values and solve for 'k'. This gives,

\frac{m_0}{2}=m_0e^{-k\times\ln 4}\\\\0.5=e^{-k\times\ln 4}\\\\Taking\ natural\ log\ on\ both\ sides,we\ get:\\\\\ln(0.5)=-k\times \ln 4\\\\k=\frac{\ln 0.5}{-\ln 4}=0.5

Hence, the equation for the mass remaining is given as:

m(t)=20e^{-0.5t}

8 0
4 years ago
A 10 kg runaway grocery cart runs into a spring with spring constant 250 n/m and compresses it by 60 cm. what was the speed of t
andrew-mc [135]
The initial kinetic energy of the cart is
K= \frac{1}{2} mv^2 (1)
where m is the mass of the cart and v its initial velocity.

Then, the cart hits the spring compressing it. The maximum compression occurs when the cart stops, and at that point the kinetic energy of the cart is zero, so all its initial kinetic energy has been converted into elastic potential energy of the spring:
U= \frac{1}{2}kx^2
where k is the spring constant and x is the spring compression.

For energy conservation, K=U. We can calculate U first: the compression of the spring is x=60 cm=0.60 m, while the spring constant is k=250 N/m, so
U= \frac{1}{2}kx^2= \frac{1}{2}(250 N/m)(0.60 m)^2=45 J

So, the initial kinetic energy of the cart is also 45 J, and from (1) we can find the value of the initial velocity:
v= \sqrt{ \frac{2K}{m} }= \sqrt{ \frac{2 \cdot 45 J}{10 kg} }  =3 m/s
7 0
3 years ago
an object 5 cm in size is placed at 30 cm in front of a concave mirror of focal length 45 CM at what distance from the mirror sh
Makovka662 [10]

Answer: Given: h₀=5cm

p=30cm

hi

f=45cm

require: q=?

hi=?

formulas:

1/f=1/p+1/q

hi/h₀=q/p

calculations:1/q=1/f-1/p

1/q=1/45-1/30

1/q=0.022=0.033

1/q=  =    -0.011

q=1/-0.011

q=   -90.91cm

hi=p × h₀/q

hi=30ₓ5/-90.91

hi=150/-90.91

hi= -1.65cm

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