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FromTheMoon [43]
2 years ago
15

Explain what atom is used as a reference when determining how many atoms are in a mole

Chemistry
1 answer:
Whitepunk [10]2 years ago
6 0

Answer: Ok so the MOLE (mol) is a unit of measurement representing the amount of a substance that contains the same number of atoms as there are molecules in exactly 12 grams of carbon-12 (i.e., 6022X1023).

Explanation: And that's how it goes, I hope you understood it well!

Best regards (Pr. El Haji)

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Use the drop-down menus to match the name and structure for the following cycloalkanes. A five-sided polygon. A square. A five-s
Mashutka [201]

Answer:

A five-sided polygon.- cyclopentane

A square.- cyclobutane

A five-sided polygon with one line extending from a point.- methylcyclopentane

A 6-sided polygon with a line extending from one point to a C H 3.- methlcyclohexane

Explanation:

7 0
3 years ago
If you were asked to run Spartan calculations on the C2H3O2-/H3O ion pair, the trend in the resulting data points would appear s
Taya2010 [7]

Answer:

a. True

Explanation:

The data curve for OCI-/H3O appears to be similar to C2H3O2-/H3O because protons have not dissociated with conjugate base. This conjugate base is strong and hold proton in solution while acids try to dissociate it.

4 0
3 years ago
Consider the reaction I2O5(g) 5 CO(g) -------> 5 CO2(g) I2(g) a) 80.0 grams of iodine(V) oxide, I2O5, reacts with 28.0 grams
Allisa [31]

Answer:

Maximum mass of I_2 produces=50.8g;

Explanation:

Firstly balance the chemical reaction,

I_2 O_5+5CO=5CO_2+I_2

Molecular weight of I_2 O_5=334g/mole;  

Molecular weight of CO =28g/mole;

Number of mole of I_2 O_5 given=80g/(334g/mole)=0.239mole;

Number of mole of CO given=28g/(28g/mole)=1 mole  

Moles are:

Number of mole of I_2 O_5=0.239

Number of mole of CO=1;

From the balanced equation,

1 mole of I_2 O_5 reacts with 5 moles of CO;

Hence;

0.239 mole of I_2 O_5  will react with 5*0.239 moles of CO means

Moles of CO that reacts with I_2 O_5  =1.2 mole but we have given 1 mole therefore

I_2 O_5 Will be excess reagent and CO will be the limitting reagent  

And mass of product depends on limiting reagent i.e. mass of CO.

5 mole of CO produces 1 moleI_2 of I_2;

1 mole of CO  produces 1/5 mole of I_2;

Maximum mass of I_2  produces=mole*molecular weight;

Molecular weight of I_2=254g/mole;

Maximum mass of   produces I_2= (1/5)*254=50.8g;

Maximum mass of I_2 produces=50.8g;

3 0
3 years ago
Is soda just opened a heterogeneous mixture?
grin007 [14]
Yes, because Google.

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Which of the following is the least important property of a mineral?
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Explanation:

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