Your answer would be C because the fire gave the marshmellow a brown crust shwoing effect.
Protons are a cluster in the centre of an atom and electrons are orbiting around the protons
Explanation:
The given reaction will be as follows.
............. (1)
= ![[Ag^{+}][Cl^{-}] = 1.8 \times 10^{-10}](https://tex.z-dn.net/?f=%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D%20%3D%201.8%20%5Ctimes%2010%5E%7B-10%7D)
Reaction for the complex formation is as follows.
........... (2)
= ![\frac{[Ag(NH_{3})_{2}]}{[Ag^{+}][NH_{3}]^{2}} = 1.0 \times 10^{8}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BAg%28NH_%7B3%7D%29_%7B2%7D%5D%7D%7B%5BAg%5E%7B%2B%7D%5D%5BNH_%7B3%7D%5D%5E%7B2%7D%7D%20%3D%201.0%20%5Ctimes%2010%5E%7B8%7D)
When we add both equations (1) and (2) then the resultant equation is as follows.
............. (3)
Therefore, equilibrium constant will be as follows.
K = ![K_{f} \times K_{sp}](https://tex.z-dn.net/?f=K_%7Bf%7D%20%5Ctimes%20K_%7Bsp%7D)
= ![1.0 \times 10^{8} \times 1.8 \times 10^{-10}](https://tex.z-dn.net/?f=1.0%20%5Ctimes%2010%5E%7B8%7D%20%5Ctimes%201.8%20%5Ctimes%2010%5E%7B-10%7D)
= ![1.8 \times 10^{-2}](https://tex.z-dn.net/?f=1.8%20%5Ctimes%2010%5E%7B-2%7D)
Since, we need 0.010 mol of AgCl to be soluble in 1 liter of solution after after addition of
for complexation. This means we have to set
=
= ![\frac{0.010 mol}{1 L}](https://tex.z-dn.net/?f=%5Cfrac%7B0.010%20mol%7D%7B1%20L%7D)
= 0.010 M
For the net reaction, ![AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq)](https://tex.z-dn.net/?f=AgCl%28s%29%20%2B%202NH_%7B3%7D%28aq%29%20%5Crightarrow%20%5BAg%28NH_%7B3%7D%29_%7B2%7D%5D%5E%7B%2B%7D%28aq%29%20%2B%20Cl%5E%7B-%7D%28aq%29)
Initial : 0.010 x 0 0
Change : -0.010 -0.020 +0.010 +0.010
Equilibrium : 0 x - 0.020 0.010 0.010
Hence, the equilibrium constant expression for this is as follows.
K = ![\frac{[Ag(NH_{3})^{+}_{2}][Cl^{-}]}{[NH_{3}]^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BAg%28NH_%7B3%7D%29%5E%7B%2B%7D_%7B2%7D%5D%5BCl%5E%7B-%7D%5D%7D%7B%5BNH_%7B3%7D%5D%5E%7B2%7D%7D)
= ![\frac{0.010 \times 0.010}{(x - 0.020)^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B0.010%20%5Ctimes%200.010%7D%7B%28x%20-%200.020%29%5E%7B2%7D%7D)
x = 0.0945 mol
or, x = 0.095 mol (approx)
Thus, we can conclude that the number of moles of
needed to be added is 0.095 mol.
The answer
would be 825000
Hope it helps!
Answer: results are based on a small sample size
Explanation:
the other answers wouldnt make sense