4. What is the instantaneous acceleration at t= 10 s?
1 answer:
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Answer:
Explanation:
<u>Given Data:</u>
Mass = m = 4 kg
Acceleration due to gravity = g = 9.8 m/s²
Height = h = 1 m
<u>Required:</u>
Potential Energy = P.E. = ?
<u>Formula:</u>
P.E. = mgh
<u>Solution:</u>
P.E. = (4)(9.8)(1)
P.E. = 39.2 Joules
Hope this helped!
<h3>~AH1807</h3>Answer:
Explanation:
The root mean square velocity of the gas at an equilibrium temperature is given by the following formula:
where,
v = root mean square velocity of molecules:
R = Universal Gas Constant
T = Equilibrium Temperature
M = Molecular Mass of the Gas
Therefore,
For T = T₁ :
For T = T₂ :
Since both speeds are given to be equal. Therefore, comparing both equations, we get:
Recall this kinematic equation:
a =
This equation gives the acceleration of the object assuming it IS constant (the velocity changes at a uniform rate).
a is the acceleration.
Vi is the initial velocity.
Vf is the final velocity.
Δt is the amount of elapsed time.
Given values:
Vi = 0 m/s (the car starts at rest).
Vf = 25 m/s.
Δt = 10 s
Substitute the terms in the equation with the given values and solve for a:
a =