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Tasya [4]
3 years ago
10

Which image is observe by seeing a distant thing using magnifying glass?

Physics
2 answers:
Snezhnost [94]3 years ago
8 0

Answer: D) Big - straight

<h2>Brainliest pls if correct!</h2>

lesya692 [45]3 years ago
7 0

Answer:

1/f = 1/o + 1 /i       thin lens equation

1 / i = 1/f - 1/o = (o - f) / (o f)    rearranging

or i = o f / (o - f)   for the image distance

This image will be positive (real) with values given

m = -i / o      magnification

m = - f / (o - f)      shows m is negative and the image inverted

Also, since o here is large m will be small and the image is small

I think they mean A as the right answer

Different texts use different terms but here i is image distance and o the object distance

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Can a body having larger mass be hotter than another of smaller mass.expalain​
Rom4ik [11]

Answer:

it would make sense because a larger body could produce more body heat.

8 0
3 years ago
a baseball is hit straight up into the air. If the initial velocity was 20 m/s, how high will the ball go?How long will it be un
AleksAgata [21]
1) The motion of the ball is an uniformly accelerated motion, with constant acceleration equal to g=-10 m/s^2 (the negative sign means it is directed towards the ground).

For an uniformly accelerated motion, we can use the following relationship:
2gh=v_f^2-v_i^2
where h is the maximum height reached by the ball, v_i = 20 m/s is its initial velocity and v_f the velocity of the ball when it reaches the maximum height. But v_f=0 (when the ball reaches the maximum height, it stops before going down, so its velocity at that moment is zero), so we can use the relationship to  calculate h, the maximum height:
h=- \frac{v_i^2}{2g} =- \frac{20 m/s)^2}{2 \cdot (-10 m/s^2)} =20 m

2) We can find the time the ball takes to return to the ground by requiring that the space covered by the ball returns to zero: 
S(t)=0
where for an uniformly accelerated motion,
S(t)=v_i t +  \frac{1}{2} gt^2 =0
By solving this, we have two solutions: one is t=0, which corresponds to the moment the player hits the ball, the second one is
t=- \frac{2 v_i}{g}=- \frac{2 \cdot 20 m/s}{-10 m/s^2}=4 s
so, the ball returns to the ground after 4 s.

3) The velocity of the ball when it returns to the ground is given by:
v(t) = v_i +gt=20 m/s + (-10 m/s^2)(4 s)=-20 m/s
where the negative sign means the ball is going downwards.
8 0
3 years ago
A crane lifts up two boxes.<br><br> Which free body diagram shows the forces acting on block A?
Temka [501]

Answer:

The 3rd graph

Explanation:

A free body diagram is a diagram which shows all the forces acting on an object.

The problem asks us to find the free body diagram of block A, so we must find all the forces acting on block A.

We have 3 forces acting on block A in total:

- The force of gravity (its weight), which pushes the block downward (in the diagram, it is the force represented with F_{gA}

- The tension in the rope 1, which pulls block A upwards: this force is represented with F_{T1}

- The tension in the rope 2, due to the weight of block 2, which pulls block A downwards: this force is represented with F_{T2}

Based on the direction of these 3 forces, the correct diagram is the 3rd one.

7 0
3 years ago
Read 2 more answers
A flat circular plate of copper has a radius of 0.262 m and a mass of 61.5 kg.
Evgesh-ka [11]

Answer:

0.031 m

Explanation:

Density of copper = ρ =  8960 kg/m³

r = Radius = 0.262 m

m = Mass of plate = 61.5 kg

v = Volume of plate = Volume of cylinder = πr²h

\rho=\frac{m}{v}\\\Rightarrow 8940=\frac{61.5}{\pi r^2h}\\\Rightarrow h=\frac{61.5}{\pi 0.262^2\times 8940}\\\Rightarrow h=0.031\ m

So, thickness of plate is 0.031 m

5 0
3 years ago
A has the magnitude 14.4 m and is angled 51.6° counterclockwise from the positive direction of the x axis of an xy coordinate sy
Ad libitum [116K]

Answer:

à in unit vector notation = 12.26485i + 7.54539j

B in unit vector notation = 16.3516i + 3.11529j

Explanation:

The detailed steps and calculation is shown in the attachment.

7 0
3 years ago
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