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12345 [234]
3 years ago
6

What is the answer ?

Chemistry
2 answers:
Diano4ka-milaya [45]3 years ago
8 0
Aaa no one has a chance of a meeting today or Friday at
insens350 [35]3 years ago
6 0

Answer: Its not popping up for me *-*?

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A gas has a pressure of 1.34 atm when the temperature is 237K. The gas is then heated until the temperature measures 312K. What
alexandr1967 [171]

The answer for the following question is answered below.

  • <em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>

Explanation:

Given:

Initial pressure of the gas = 1.34 atm

Initial temperature of the gas = 273 K

final temperature of the gas = 312 K

To solve:

Final temperature of the gas

We know;

From the ideal gas equation

P × V = n × R × T

So;

from the above equation we can say that

    <em>P ∝ T</em>

     \frac{P}{T} = constant  

     \frac{P_{1} }{P_{2} } = \frac{T_{1} }{T_{2} }

Where;

P_{1} = initial pressure of a gas

P_{2} = final pressure of a gas

T_{1} = initial temperature of a gas

T_{2} = final temperature of  a gas

    P_{2} = \frac{1.34*312}{237}

    P_{2}  = 1.76 atm

<em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>

6 0
3 years ago
A mixture of ch4 and h2o is passed over a nickel catalyst at 1000. k. the emerging gas is collected in a 5.00-l flask and is fou
Scrat [10]
                    
According to that Kc is an equilibrium constant in terms of molar concentrations.
and Kc = [C]^c *[D]^d / [A]^a * [B]^b >>>> (1)
in the general reaction:
aA + bB ↔ cC + dD 
and, from our balanced equation:
CH4 + H2O ⇔ Co + 3H2 >>> (2)
So, we need to calculate the concentrations (molarity) of the products and reactants:
the Molarity of CH4 = no. of moles/volume (L)
 and no. of moles = weigh / Molecular weight = 42.3 / 16 = 2.643 moles
so the molarity of CH4 = 2.643 / 5 = 0.528 molar
the molarity of H20 = (49.2 / 18) / 5 =  0.546 molar
the molarity of CO = (8.32/28) / 5 = 0.059 molar
the molarity of H2 = (2.63 / 2) / 5 = 0.263 molar 
By substitution in (1) according to (2);
∴ Kc = [0.059]*[0.263]^3 / ( [0.528]*[0.546]) = 3.7 * 10 ^-3  >>>> (3)
Kp = Kc (RT)^(Δn) >>> (4)
where R is the gas constant = 0.0821,
and Δn is the change in moles in gas= (3(H2) + 1 (CO) - (1 H2O + 1 CH4) = 2
by substition in (4):
∴ Kp = 3.7*10^-3 (0.0821* 1000)^2= 24.939



3 0
3 years ago
(40 Points) Complete, balance, compute the amounts of the products assuming 100% yield. 12g Zinc Solid + 24g Silver Nitrate
VARVARA [1.3K]

Answer:

Zn + 2AgNO₃ → Zn(NO₃)₂ +2Ag

13.34g Zn(NO₃)₃ and 15.24g Ag are formed if reaction is 100% complete.

Explanation:

molar mass of Zn=65 g

molar mass of AgNO₃=170 g

molar mass of Zn(NO₃)₂ =189  g

molar mass of Silver = 108 g

Zn + 2  AgNO₃ → Zn(NO₃)₂ +2 Ag            eq(1)

1 mole Zn  reacts with 2 moles Silver nitrate to give 1 mole Zinc nitrate and 2 moles Silver

or

65 g Zn reacts with 2×170 g of AgNO₃  → 189 g Zn(NO₃)₂ and 2×108 g Ag    - eq(2)

First find limiting reagent of the reaction

65g Zn reacts with 2×170g of AgNO₃

12 g Zn reacts with (12÷65)×2×170 g AgNO₃

=62.7 g AgNO₃

For the reaction to go to 100% yield 12 g Zn will need 62.7 g AgNO₃

but amount of AgNO₃ is 24 g

So the reaction yields is limited by amount of AgNO₃.

AgNO₃ is the limiting reagent.

So calculate the yield of products with the amount of AgNO₃

by eq(2)

2× 170 gAgNO₃ gives 189 g Zn(NO₃)₃

=340 g AgNO₃ gives 189 g Zn(NO₃)₃

24 g AgNO₃ gives (24÷340) ×189 g Zn(NO₃)₃

=13.34g Zn(NO₃)₃

again by eq2

2×170 g AgNO₃ gives 2×108 g Ag

= 340 g AgNO₃ gives 216 g Ag

24 g AgNO₃ gives (24÷340)×216 g Ag

= 15.24g Ag

6 0
3 years ago
What is the molar concentration of the B⁻ ions in 0.22 M XB₃(aq)?
Snowcat [4.5K]
In this question, XB3(aq) is an ionic compound which will have the releasing of 3 B⁻ ions ions in water for every molecule of XB3 that dissolves.
XB3(s) --> X+(aq) + 3 B⁻(aq)
            [B⁻] = 0.22 mol XB3/1L × 3 mol B⁻ / 1 mol XB3 = 0.66 M
The answer to this question is [B⁻] = 0.66 M
6 0
3 years ago
Which option correctly matches the chemical formula of a compound with its
azamat

Answer:

B. NO₂, nitrogen dioxide

Explanation:

Nitrogen dioxide is one of the oxides of nitrogen. It reacts highly and is very harmful for the health of humans. It is regarded as one of the pollutants of the air pollution. The chemical formula of Nitrogen dioxide is NO₂. This gas is produced during the manufacturing of the fertilizers in the industries. Burning of the fossil fuels also contribute in the emission of nitrogen dioxide. Two atoms of oxygen when reacts with one atom of Nitrogen, Nitrogen dioxide is formed.

6 0
2 years ago
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