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serg [7]
3 years ago
14

In the alkane series of hydrocarbons, as the number of carbon atoms decreases, the normal boiling point ofthe compounds

Chemistry
1 answer:
noname [10]3 years ago
3 0
<span>The relationship between the number of carbon atoms and boiling point is inversely proportional. In the alkane series of hydrocarbons, as the number of carbon atoms decreases, the normal boiling point of the compounds decreases. The reason behind this is that longer chains of molecules require more energy to separate the bonds while shorter chains or molecules with lower number of carbon atoms require less energy to break away from each other. Thus, low carbon molecules have lower boiling point.</span>
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What are the various adverse effects of chemistry​
Kisachek [45]

<u>Answer:</u>

<em>Chemistry is the reaction between certain elements to </em><em>create a new compound</em><em> which may happen naturally but is mostly man made and hence has lot of good as well as </em><em>adverse effects.</em>

<u>Explanation:</u>

The <em>product or compound</em> that we get and the energy or outcome we receive is the ultimate result that decides whether chemical reaction that has happened is good or bad.

There are reactions that may cause pain and suffering to living beings and  are also able to<em> Infuse damage and destruction</em> are are adverse nature. they can also change the course of nature hence are are <em>dangerous. </em>

4 0
3 years ago
A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
a_sh-v [17]

Answer:

m_{H_2O}=39.0g

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g

Best regards.

8 0
3 years ago
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Answer: the ability to be dissolved, especially in water.

Explanation: I think the answer you've picked is right

Hope this helps

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The first-order decay of radon has a half-life of 3.823 days. How many grams of radon remain after 7.22 days if the sample initi
Nesterboy [21]

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Question 4
ruslelena [56]

Answer:

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Explanation:

Brainliest would be appreciated

7 0
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