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motikmotik
3 years ago
7

The gravitational force of the Earth exerts no torque on a satellite orbiting the Earth in an elliptical orbit. Compare the moti

on of the satellite at the point in its orbit nearest the Earth (perigee) to its motion at the pint in it orbit farthest from the Earth (apogee). At these two points closest to the earth:
A) the angular speed will be greatest although the linear speed will be the same.B) the kinetic energy and angular momentum will both be greater.C) None of the above.D) Both choices A and B are valid.
Physics
1 answer:
stealth61 [152]3 years ago
4 0

Answer:

3) None of the above

Explanation:

In orbital motion

by lepler law:

Planet sweeps out equal area in equal of time, so angular velocity is conserved.

Angular momentum is also conserved,

so option, 3) None of the above is right.

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Starting at (0,0) an object travels 36 meters north and then it covers 20 meters east. What is
Svetradugi [14.3K]

Answer:

Explanation:

Using the pythagoras theorem, the displacement is expressed as;

d² = x²+y²

y = 36m (north)

x = 20m east

Substitute;

d² = 36²+20²

d² = 1296+400

d² = 1696

d = √1696

d = 41.18m

For the direction;

theta = tan^-1(y/x)

theta = tan^-1(36/20)

theta = tan^-1(1.8)

theta = 60.95°

Hence the magnitude is 41.18m and the direction is 60.95°

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3 years ago
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lyudmila [28]

Answer: Answer to the I'm Tall when I'm Young, and I'm Short when I'm Old. What am I? Riddle is a candle

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7 0
2 years ago
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The graph shows the number of beans eaten by a
il63 [147K]

Answer:

You didn't show a graph

Explanation:

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3 years ago
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How many full length strands of hair are collected from the scalp to use as a sample?
laila [671]
50 strands is the standard procedure
4 0
3 years ago
A 180 lb crate is on the ground, and a strong rope is attached. You need to move it across the basement floor, which has a coeff
jekas [21]

Answer:

F = 505.13 N

Yes it is better to pull the rope rather than push it

Explanation:

Let the force is applied at an angle of 60 degree

so we will have net vertical force on the crate is given as

F_n + Fsin60 = mg

here we know

m = 180 lb

m = 81.65 kg

F_n = 81.65(9.81) - Fsin60

F_n = 801 - 0.866 F

now friction force on the crate is given as

F_x = \mu F_n

Fcos60 = 0.7(801 - 0.866 F)

0.5F + 0.61F = 560.7

F = 505.13 N

Yes it is better to pull the rope rather than push it

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3 years ago
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