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Orlov [11]
3 years ago
10

How can your life be negatively impacted by not being scientifically literate in today's world?

Physics
1 answer:
aksik [14]3 years ago
6 0

Answer:

may be or sometimes not

Explanation:

It depends on those who Surround you and your confidence

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8. How much energy was expended by a rocked that is launched at 90 degrees
svlad2 [7]

Answer:

b.

because hsuehwbwnowbwbww9whw

6 0
3 years ago
A given individual is unable to see objects clearly when he is beyond 60 cm. What power lens should be used to correct this prob
Sveta_85 [38]

Answer:

correct option is E

power lens is - 1.667 D

Explanation:

Given data

infinity = 60 cm

to find out

power lens

solution

we know here infinity v = -60 cm because object at infinity

and we take u  = - infinity

so we know that

1/f = 1/v - 1/u

1/f = 1 / -60  - 1 / -infinity

so

1/f = - 1/60

f = - 60 cm = 0.60 m

and we know power of lens = 1/f

so here

power = 1 / -0.60

power = - 1.667 D

so correct option is E

power lens is - 1.667 D

6 0
4 years ago
How does universal gravitation affect you and objects around you?
Olegator [25]

<u>Answer</u>:

Newton proposed the "law of Universal Gravitation". He said that gravity is universal in nature and it affects all the objects. Gravity is present between you and every object having mass around you. The "Strength of the gravity" between two objects with mass is depends on the product of masses and distance between the objects.

The "Gravitational force" increases with the increase in mass of the objects and decreases with the increase in distance between the objects. The gravity exerts a force on every object. The direction of force of gravity is towards the centre of the Earth.  

 

8 0
3 years ago
A certain electric dipole consists of charges q and –q separated by distance d, oriented along the x-axis as shown in the figure
Anna71 [15]

Electric field due to a point charge is given by formula

E = \frac{kq}{r^2 + \frac{d^2}{4}}

now due to negative charge also the magnitude of electric field will be same

only difference is the direction of field due to negative charge is radially inwards

now we can say that net field due to these two charges is given as

E = 2E_0cos\theta

E = 2\frac{kq}{r^2 + \frac{d^2}{4}}*\frac{d/2}{\sqrt{r^2 + \frac{d^2}{4}}}

E = \frac{kqd}{(r^2 + \frac{d^2}{4})^1.5}

now it is given that distance r is very large than "d" so we can say

E = \frac{kqd}{r^3}

<em>so above is the electric field due to dipole</em>

7 0
3 years ago
How would you go about measuring the speed of a vehicle? What measurements would you have to take? What calculations would you h
White raven [17]

Answer:

For a body moving at a uniform velocity you can calculate the speed by dividing the distance traveled by the amount of time it took, for example one mile in 1/2 hour would give you 2 miles per hour. If the velocity is non-uniform all you can say is what the average speed is.

3 0
3 years ago
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