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2 years ago

5

A ball is moving at 2 m/s and has a momentum of 12 kg•m/s. What is the ball's mass?

1 answer:

Mama L [17]2 years ago

6 0

Answer:

6 kg

Explanation:

p = mv

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What is efficiencywhat is the formula of mechanical advantage and velocity ratio of labour

sdas [7]

Answer:

Mechanical Advantage = Output Force/Input Force

Velocity Ratio = Driving Gear/Driven Gear

Explanation:

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3 years ago

Waves A and B have the same speed, but wave A has a shorter wavelength. Which wave has the higher frequency?

Nuetrik [128]

Frequency and wavelength are inversely proportional.
A shorter wavelength implies a higher frequency.

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3 years ago

If you heat a thin, circular ring in the oven, does the rings hole get larger or smaller?

KiRa [710]

Unless the ring by design will have restriction for any outward expansion. The hole will get larger / bigger as you heat this up. The more you heat an object the more it expands, thus the larger the hole gets. The only case is when outward expansion is restricted, the expansion will be inward as it is the only direction the ring can expand to.

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3 years ago

You have a stopped pipe of adjustable length close to a taut 85.0cm, 7.25g wire under a tension of 4170N. You want to adjust the

Makovka662 [10]

Answer:

The length is $L_d= 0.069 \ m$

Explanation:

From the question we are told that

The length of the wire $L = 85cm = \frac{85}{100} = 0.85m$

The mass is $m = 7.25g = \frac{7.25}{1000} = 7.25^10^{-3}kg$

The tension is $T = 4170N$

Generally the frequency of oscillation of a stretched wire is mathematically represented as

$f = \frac{n}{2L} \sqrt{\frac{T}{\mu}$

Where n is the the number of nodes = 3 (i.e the third harmonic)

$\mu$ is the linear mass density of the wire

This linear mass density is mathematically represented as

$\mu = \frac{m}{L}$

Substituting values

$\mu = \frac{7.2*10^{-3}}{0.85}$

$= 8.53 *10^{-3} kg/m$

Substituting values in to the equation for frequency

$f = \frac{3}{2 80.85} * \sqrt{\frac{4170}{8.53*10^{-3}} }$

$= 1234Hz$

From the question the we can deduce that the fundamental frequency is equal to the oscillation of a stretched wire

The fundamental frequency is mathematically represented as

$f = \frac{v}{4L_d}$

Where $L_d$ is the length of the pipe

v is the speed of sound with a value of $v = 343m/s$

Making $L_d$ the subject of the formula

$L_d = \frac{v}{4f}$

Substituting values

$L_d = \frac{343}{(4)(1234)}$

$L_d= 0.069 \ m$

From the question the we can deduce that the fundamental frequency is equal to the oscillation of a stretched wire

6 0

3 years ago

You record the spectrum of a star and find that a calcium absorption line has an observed wavelength of 394.0 nm. This calcium a

saveliy_v [14]

Answer:

radial velocity = 0.533 × $10^{6}$ m/s

Explanation:

given data

observed wavelength = 394.0 nm

rest wavelength = 393.3 nm

solution

we get here radial velocity by the Doppler effect of light that is

$\frac{\triangle \lambda }{\lambda} = \frac{v}{c}$ ......................1

v = $\frac{c \times \triangle \lambda }{\lambda}$

put here value

v = \frac{c \times (\lambda ' - \lambda }{\lambda}

v = \frac{3 \times 10^8 \times (394 - 393.3}{393.3}

v = 533943.55

v = 0.533 × $10^{6}$ m/s

8 0

4 years ago