Taking into account the reaction stoichiometry, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.
<h3>Reaction stoichiometry</h3>
In first place, the balanced reaction is:
2 AgBr + Na₂S₂O₃ → Ag₂S₂O₃ + 2 NaBr
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- AgBr: 2 moles
- Na₂S₂O₃: 1 mole
- Ag₂S₂O₃: 1 mole
- NaBr: 2 moles
The molar mass of the compounds is:
- AgBr: 187.77 g/mole
- Na₂S₂O₃: 158 g/mole
- Ag₂S₂O₃: 327.74 g/mole
- NaBr: 102.9 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- AgBr: 2 moles ×187.77 g/mole= 375.54 grams
- Na₂S₂O₃: 1 mole ×158 g/mole= 158 grams
- Ag₂S₂O₃: 1 mole ×327.74 g/mole= 327.74 grams
- NaBr: 2 moles ×102.9 g/mole= 205.8 grams
<h3>Mass of Ag₂S₂O₃ formed</h3>
The following rule of three can be applied: if by reaction stoichiometry 375.54 grams of AgBr form 327.74 grams of Ag₂S₂O₃, 125 grams of AgBr form how much mass of Ag₂S₂O₃?

<u><em>mass of Ag₂S₂O₃= 109.09 grams</em></u>
Then, 109.09 grams of Ag₂S₂O₃ are formed when 125 g AgBr reacts completely.
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A volcano would most likely occur on a divergent boundary, as these boundaries push plates together, resulting in the formation of a mountain or a volcano.
Explanation:
Carbon black sphere
Nitrogen blue sphere
Chlorine green sphere
Hydrogen white sphere
Reactants:
three molecules that contain one black sphere and four white spheres
3CH₄
three molecules that contain two blue spheres and four green spheres:
3N₂Cl₄
Products:
three molecules that contain one black sphere and four green spheres:
3CCl₄
three molecules that contain two blue spheres:
3N₂
six molecules that contain two white spheres
6H₂
The reaction proper:
3CH₄ + 3N₂Cl₄ → 3CCl₄ + 3N₂ + 6H₂
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Answer:
Organelles that use energy from sunlight to produce food are called mitochondria.
False
Answer:
58.944 g
Explanation:
From the question given above, the following data were:
Mole of SO2 = 0.9210 mole
Mass of SO2 =?
Next, we shall determine the molar mass of SO2. This can be obtained by adding the molar mass of sulphur and oxygen together as illustrated below:
Molar mass of SO2 = 32 + (2 × 16)
= 32 + 32 = 64 g/mol
Finally, we shall determine the mass of 0.9210 mole of SO2 as follow:
Mole of SO2 = 0.9210 mole
Molar mass of SO2 = 64 g/mol
Mass of SO2 =?
Mole = mass /Molar mass
0.9210 = mass of SO2 / 64
Cross multiply
Mass of SO2 = 0.9210 × 64
Mass of SO2 = 58.944 g
Thus, the mass of SO2 is 58.944 g.