Well, you could use a reverse osmosis process to remove all of the fluoride that the United Staes government has put in the water! Every year the Us Gov receives a lot of fluoride from china. Fluoride is a waste and a poison, and instead of the Us Government paying a Buch of money to burn this waste, they just put it in the water! what you need t do, is get your water from the earth. Which is actually the best place to get your water, because its WATER filtered by the earth. Just google wells or springs around your location, some private business/companies offer their water collecting serves, something you should really take advantage of! As for me, I get my water at a place called "Carlsbad alkaline water." good stuff, only 50 cents for 4 gallons. rawr XD Jesus loves you, and he offers the everything freely, which means you don't need to follow a religion to earn anything. Lets face it, your not perfect, and we need help from God!
Answer:
2.6 g
Explanation:
Percent concentration = 5%
Volume of water = 50ml
Since 1ml of water = 1g of water
Mass of water= 50g
Let the mass of sucrose be x
Mass% = mass of solute/mass of solute + mass of solvent × 100
5= x/x+ 50 ×100
5/100 = x/x + 50
0.05 = x/x + 50
0.05(x + 50) = x
0.05x + 2.5 = x
2.5 = x - 0.05x
2.5 = 0.95x
x= 2.5/0.95
x=2.6 g
<h3>Answer:</h3>
When a disulfide linkage is formed, the compound containing this new linkage has been <u>oxidized</u>.
<h3>Explanation:</h3>
Oxidation reaction is defined as,
i) Addition of Oxygen Atoms:
When oxygen atom is added to any compound, then the compound is said to be oxidized and the reaction is known as oxidation reaction.
Example:
Oxidation of Alcohols into carboxylic acids:
R---CH₂--OH → R---COOH
ii) Removal of Hydrogen Atoms:
When hydrogen atom(s) are removed from any compound, then the compound is said to be oxidized and the reaction is also called as oxidation reaction.
Example:
Formation of disulfide bond fro thiols:
R--S-H + R--S-H → R---S--S---R
Disulfide bond is quite popular in protein chemistry where it is formed in cystine from cystein amino acids.
Answer:
6.94 amu
Explanation:
Step 1: Given data
- Mass of ⁶Li (m⁶Li): 6.0151223 amu
- Abundance of ⁶Li (ab⁶Li): 7.5% (0.075)
- Mass of ⁷Li (m⁷Li): 7.0160041 amu
- Abundance of ⁷Li (ab⁷Li): 92.5% (0.925)
Step 2: Calculate the average atomic mass (aam) of Li
We will use the following expression.
aam = m⁶Li × ab⁶Li + m⁷Li × ab⁷Li
aam = 6.0151223 amu × 0.075 + 7.0160041 amu × 0.925
aam = 6.94 amu
