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Salsk061 [2.6K]
3 years ago
7

Which tool would you use to measure at what temperature a solution boils?

Physics
2 answers:
Varvara68 [4.7K]3 years ago
5 0

Personally, I would choose the thermometer for that particular measurement ... especially if I were pressed for time.

The thermometer will deliver the fastest, most precise, most accurate measurement, since scales, rulers, and stopwatches are not designed to measure temperature at all.

Mekhanik [1.2K]3 years ago
4 0

Answer: you would use a thermometer

Explanation: why a thermometer? Because a thermometer is the only way a solution can be measured in the context of temperatures. By only way, I mean the hold of the device mentioned in the question

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I think C. 33 newtons
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Does passing a magnet through a coil of wire break off it’s electric current
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7 0
2 years ago
An airplane is moving at 350 km/hr. If a bomb is
Molodets [167]

Answers:

a) -171.402 m/s

b) 17.49 s

c) 1700.99 m

Explanation:

We can solve this problem with the following equations:

y=y_{o}+V_{oy}t-\frac{1}{2}gt^{2} (1)

x=V_{ox}t (2)

V_{f}=V_{oy}-gt (3)

Where:

y=0 m is the bomb's final jeight

y_{o}=1.5 km \frac{1000 m}{1 km}=1500 m is the bomb'e initial height

V_{oy}=0 m/s is the bomb's initial vertical velocity, since the airplane was moving horizontally

t is the time

g=9.8 m/s^{2} is the acceleration due gravity

x is the bomb's range

V_{ox}=350 \frac{km}{h} \frac{1000 m}{1 km} \frac{1 h}{3600 s}=97.22 m/s is the bomb's initial horizontal velocity

V_{f} is the bomb's fina velocity

Knowing this, let's begin with the answers:

<h3>b) Time</h3>

With the conditions given above, equation (1) is now written as:

y_{o}=\frac{1}{2}gt^{2} (4)

Isolating t:

t=\sqrt{\frac{2 y_{o}}{g}} (5)

t=\sqrt{\frac{2 (1500 m)}{9.8 m/s^{2}}} (6)

t=17.49 s (7)

<h3>a) Final velocity</h3>

Since V_{oy}=0 m/s, equation (3) is written as:

V_{f}=-gt (8)

V_{f}=-(97.22)(17.49 s) (9)

V_{f}=-171.402 m/s (10) The negative sign ony indicates the direction is downwards

<h3>c) Range</h3>

Substituting (7) in (2):

x=(97.22 m/s)(17.49 s) (11)

x=1700.99 m (12)

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URGENTTT PLEASE HELPPPP. You put m1 = 1 kg of ice cooled to -20°C into mass m2 = 1 kg of water at 2°C. Both are in a thermally i
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Answer:

Explanation:

heat lost by water will be used to increase the temperature of  ice

heat gained by ice

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1 x 2090 x t

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= mcΔt  where m is mass of water , s is specific heat of water and Δt is fall in temperature .

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8372

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1 x 2090 x t  = 8372

t = 4°C

There will be a rise of  4 degree in the temperature of ice.  

 

5 0
2 years ago
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