Mass (g) / Volume (cm^3) = Density (g/cm^3)
60.4g/ 11.3 cm^3 = 5.35 g/cm^3
d= 5.35 g/cm^3
TESTS USED-
Spectroscopic method is used to determine unknown substances found in wildlife waters.
IMPORTANCE-
<span>To control the quality of fish.
</span>TESTS USED -
Blood or urine tests are used for analysis
Gas chromatography is the most common method of chemical analysis
IMPORTANCE -
<span>to avoid cheating in sports</span>
Answer:
Moles of water in 7.1×10²⁵ molecules are 118 mol.
Explanation:
Given data:
Number of molecules of water = 7.1×10²⁵ molecules
Moles of water in 7.1×10²⁵ molecules = ?
Solution;
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
1 mole = 6.022 × 10²³ molecules of water
7.1×10²⁵ molecules of water × 1 mol / 6.022 × 10²³ molecules of water
1.18×10² moles of water 0r 118 moles of water
A cold front is the leading edge of a cooler mass of air, replacing at ground level a warmer mass of air, which lies within a fairly sharp surface trough of low pressure.