Answer:
x = 50 N
Explanation:
Given that we have a net force, a mass, and acceleration, we can use the fundamental formula for force found in newton's second law which is F = m × a.
Given a mass of 150 kg, and an acceleration 3.0m/s². We can substitute these two values in our formula to calculate the magnitude of these forces or it's net force to identify the unknown force acting on our known force for this situation to work.
_______
F (Net force) = F2 (Second force which we are given) - F1 (First force) = m × a
m (mass which we are given) = 150 kg
a (acceleration which we are given) = 3.0m/s
________
So F = m × a → F2 - F1 = m × a →
500 - F1 = 150 × 3.0 → 500 - F1 = 450 →
-F1 = -50 → F1 = 50
Answer:
1 m/s^2
Explanation:
The formula for accleration is a=Δv/Δt
where, Δv = final velocity - initial velocity = 4 - 0 = 4
initial velocity = 0 since the car starts form rest and final velovity is 4 as the car goes from rest till 4 m/s
Δt = 4 since the car takes 4 seconds to reach a velocity of 4m/s
Hence, a = 4 m/s / 4 s = 1 m/s^2
Answer / Explanation:
Referencing the diagram of a resonance in a vertical tube as illustrated in the attached diagram below,
we can say that:
Vertical wave is the result of superposition of dual and identical waves.
We should also note that the only difference is that they travel in opposite directions to each other.
So, let assume a tuning fork is vibrated with frequency ν
at the open end of the tube of varying length which can be changed during vibration with the help of water level change.
Also, let us assume the minimum length of the tube be L, when the resonance is heard.
Also, we assume that 1/4 of the wavelength λ
of the standing wave is equal to length of the minimum length L of the tube.
Hence, we have:
λ = 4
L
.
So, if speed of sound in air is V
, then frequency of the tuning fork can be expressed as:
U = v / λ = v / 4L
Noting that we have been given the speed of sound in air as V = 343
m
/
s
.
where:
U = v / λ = v / 4L
therefore,
343
m
/
s / 4 x 0.5525 m
= 155.20 Hz
Noting that 1 wave length in centimeter is 29979245800 Hz
Therefore, I wavelength in centimeter = 29979245800 Hz / 155.20 Hz
= 193 cm
Answer:
Record your measured values of displacement and velocity for times t = 8.0 seconds and t = 10.0 seconds in the columns below.
Next, use the measured displacement and velocity values at t = 7.0 seconds and t = 9.0 seconds to interpolate the values of displacement and velocity at t = 8.0 seconds.
Use the following formula to interpolate and extrapolate. Remember, x and y here represent values on the x and y axes of the graph. The x values will really be time and the y values will be either displacement (x) or velocity (vx).
Explanation:
Record your measured values of displacement and velocity for times t = 8.0 seconds and t = 10.0 seconds in the columns below.
Next, use the measured displacement and velocity values at t = 7.0 seconds and t = 9.0 seconds to interpolate the values of displacement and velocity at t = 8.0 seconds.
Use the following formula to interpolate and extrapolate. Remember, x and y here represent values on the x and y axes of the graph. The x values will really be time and the y values will be either displacement (x) or velocity (vx).
This is the answer