Question

The net negative charge flowing through a device varies as q(t) = 2.2 t2 C. Find the current through the device at t = 0, 0.5, and t= 1 s.

Answer 1

Answer:

The current at t= 0 sec, is 0 A

The current at t= 0.5 sec, is 2.2 A

The current at t= 1 sec, is 4.4 A

Explanation:

Given that

q(t) = 2.2 t²

We know that:- the change in the charge w.r.t. time is known as current. So,

$I=\dfrac{dq}{dt}$

q(t) = 2.2 t²

$\dfrac{dq}{dt}= 4.4 t$

I= 4.4 t

1.

t = 0 s :

I = 4.4 x 0 = 0 A

Therefore, the current at t= 0 sec, is 0 A

2 .

t= 0.5 s :

I = 4.4 x 0.5 = 2.2 A

Therefore, the current at t= 0.5 sec, is 2.2 A

3.

t= 1 s

I = 4.4 x 1 =4.4 A

Therefore, the current at t= 1 sec, is 4.4 A